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3 years ago

A ___________ chain is a sequence of amino acids that is the foundation for the basic structure of a protein.

Physics

2 answers:

jeka943 years ago

6 0

Answer:

A polypeptide chain is a sequence of amino acids that is the foundation for the basic structure of a protein.

Explanation:

The amino acids are composed of an organic molecule with an amino group and a carboxyl group. Its combination forms proteins, which are essential for our body. They are formed of carbon, oxygen, hydrogen and nitrogen. Among its functions, amino acids help break down food and repair body tissues.

Proteins consist of one or more amino acid chains; These chains are called polypeptides. These are peptides when the chains are composed of at least ten amino acids. Then a polypeptide, in other words, is a sequence of amino acids that are linked through peptide bonds. If the chained amino acids are more than a hundred, then we talk about protein. Proteins, therefore, are made of polypeptide chains.

Generally a polypeptide contains between 50 and 100 amino acids.

So:

A polypeptide chain is a sequence of amino acids that is the foundation for the basic structure of a protein.

NNADVOKAT [17]3 years ago

5 0

Polypeptide is the answer

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3 years ago

Volume of 10 coin is 25ml what is the volume of 1 coin

timama [110]

Answer: 2.5 ML

Explanation:

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3 years ago

1. A fixed pulley is a machine that increases the effort force.

IRISSAK [1]

For the specific questions given, these would be the answers:

1) False

2) False

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6 0

3 years ago

A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m twice every second, what is the tension i

Svetradugi [14.3K]

Answer:

T = 19.75 N

Explanation:

given,

mass of ball = 0.25 Kg

radius = 0.5 m

frequency = 2 s⁻¹

tension in the string = ?

angular velocity

ω = 2 π f

ω = 2 π x 2

ω = 12.57 rad/s

tension on the string is equal to the centripetal force

T = m ω² r

T = 0.25 x 12.57² x 0.5

T = 19.75 N

Tension in the string is equal to T = 19.75 N

3 0

3 years ago

You and a partner sit on the floor and stretch out a coiled spring to a length of 7.2 meters. You shake the coil so you

vekshin1

Answer:

Approximately $5.9\; {\rm m\cdot s^{-1}}$ (assuming that the partner is holding the other end of the coil stationary.)

Explanation:

In a standing wave, an antinode is a point that moves with maximal amplitude, while a node is a point that does not move at all. There is an antinode between every two adjacent nodes. Likewise, there is a node between every two adjacent antinodes.

The side of the spring that is being shaken moving with maximal amplitude. Hence, that point on this spring would also be an antinode. In contrast, the side of the spring that is held still (does not move at all) would be a node.

There would be a node between:

the antinode at the end of the spring that is being shaken, and
the antinode between the two ends of this spring.

Overall, the nodes and antinodes on this spring would be:

node at the end that is being held still,
antinode (as mentioned in the question),
node (inferred, not mentioned in the question), and
antinode at the end that is being shaken.

The distance between two adjacent nodes is equal to one-half (that is, $(1/2)$ ) the wavelength of the wave. The distance between a node and an adjacent antinode is one-quarter (that is, $(1/4)$ ) of the wavelength of the wave.

Thus, if the wavelength of the wave in this question is $\lambda$ , the length of this spring would be:

$\displaystyle \frac{1}{2}\, \lambda + \frac{1}{4}\, \lambda = \frac{3}{4}\, \lambda$ .

The question states that the length of this coiled spring is $7.2\; {\rm m}$ . In other words, $(3/4) \, \lambda = 7.2\; {\rm m}$ . The wavelength of this wave would be $(7.2\; {\rm m}) / (3/4) = 9.6\; {\rm m}$ .

The frequency $f$ of this wave is the number of cycles in unit time:

$\begin{aligned} f &= \frac{10}{16.3\; {\rm s}} \approx 0.613\; {\rm s^{-1}}\end{aligned}$ .

Hence, the speed $v$ of this wave would be:

$\begin{aligned} v &= \lambda\, f \\ &=9.6\; {\rm m} \times 0.613\; {\rm s^{-1}} \\ &\approx 5.9\; {\rm m \cdot s^{-1}}\end{aligned}$ .

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2 years ago