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strojnjashka [21]
3 years ago
11

What is the distance between a 2000 kg truck and a 3000 kg truck if the gravitational force between them is 0.00006 N?

Physics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

A. 2.58m

Explanation:

Using the formula;

F = GMm/r²

M and  m are the masses

G is the gravitational constant

r is the distance between the masses

Substitute

0.00006 = 6.67*10^-11(2000)(3000)/r²

0.00006r² = 6.67*10^-11*6000000

0.00006r² = 40.02*10^-5

0.00006r² = 0.0004

r² =  0.0004/0.00006

r² = 6.66

r = 2.58m

Hence the distance between them is 2.58m

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3 years ago
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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init
Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

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n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

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δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

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δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

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3 0
3 years ago
A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
Fantom [35]

Answer:

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Explanation:

given data

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radius = 1.20 cm

solution

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so

- q × E = m × w² × r     ..................1

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}r} q =  m × w² × r   ............2

and w = \frac{2*\pi}{T}  

w = \frac{d\theta }{dt}

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so here from equation 2

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8 0
3 years ago
Water is an example of ___________, while hydrogen is an example of __________.
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3 years ago
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Everything is in the pic.
nikitadnepr [17]
The answer is A

Good luck!
3 0
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