Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
(20 miles/inch) * (3.5 inches) = 70 miles
Step-by-step explanation:
Answer:
19
Step-by-step explanation:
Inscribed Angle = 1/2 Intercepted Arc
< DBG = 1/2 ( DG)
< DBG = 1/2 ( 360 - BD - BG)
= 1/2 ( 360 - 172 - 150)
= 1/2 (38)
= 19
Answer:
D. The system is in echelon form.
Step-by-step explanation:
Check attachment
Answer:
x=35.5
Step-by-step explanation:
reduce numbers
remove parentheses
add the numbers
move constant to the right
subtract numbers