Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:
Step-by-step explanation:
51 / 13 = 3.9231 = 3
51 - (13 x 3) = 12
Answer: 9 remainder 2
Explanation: 9 is the closest 6 can get to 56 without going over. Since 9•6=54, and 56-54=2 , 2 is the remainder.
Answer:
2 x
— = —
25 700
700(2)= 25(x)
1400/25=x
x=56
Step-by-step explanation:
Answer:
i think its 320
Step-by-step explanation:
i looked it up
