Ask question

Ask question

All categories

3 years ago

9

Find the sum of the following infinite geometric series, if it exists. 2 + 6 + 18 + 54 +…And when you answer this question ive s

een a lot of people just adding it together and saying thats the answer and that is not how you do it

1 answer:

Phantasy [73]3 years ago

7 0

Its multiplied by three each time

You might be interested in

How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

$2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1$

and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

6 0

3 years ago

How many 4 digit codes are possible if the first digit cannot be 0 and digits can be repeated?

bezimeni [28]

Answer: 9,000

Step-by-step explanation: there are 9 number options for the first digit and 10 for the other 3, so 9x10x10x10=9000

4 0

3 years ago

Need help on these question

hoa [83]

1.

* D'C'

* 90

2.

* C (10, -5)

6 0

3 years ago

Anwen walks at an average

Roman55 [17]

Answer:

7 km

Step-by-step explanation:

2 hours 20 minutes is 2 and 1/3 hours. 3 * 2 and 1/3 = 3 * 7/3 = 7km.

4 0

3 years ago

Read 2 more answers

f(x) = x2. What is g(x)?SIf(x)= x/g(x)(2,1)-5O A.06)-()O B. g(x) = 2x2O C. g(x)-9(x)=(*)O D. g(x)= x2

Andrew [12]

Explanation

As you can see all the possible answers have the same form:

$g(x)=ax^2$

By looking at the picture you'll notice that the graph of g(x) has to pass through the point (2,1). Remember that the points in the graph of g(x) have the form (x,g(x)). Since (2,1) is part of the graph of g(x) then we have the following:

$\begin{gathered} (2,1)=(x,g(x)) \\ x=2 \\ g(2)=1 \end{gathered}$

So let's evaluate the expression for g(x) that we wrote before at x=2. This way we'll obtain an equation for the number a:

$\begin{gathered} g(2)=1=a\cdot2^2 \\ 1=4a \end{gathered}$

Then we can divide both sides by 4:

$\begin{gathered} \frac{1}{4}=\frac{4a}{4} \\ a=\frac{1}{4} \end{gathered}$

Then we get:

$g(x)=\frac{1}{4}x^2=(\frac{1}{2}x)^2$ Answer

Then the answer is option A.

3 0

1 year ago