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DIA [1.3K]
3 years ago
11

Logbase3 (x+2)= log base3 (2x^2-1) steps 1 through 6

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

log_3(x+2)=log_3(2x^2-1)\\3^{log_3(x+2)}=3^{log_3(2x^2-1)}\\x+2=2x^2-1\\-x -2       -x -2\\0=2x^2-x-3\\2*-3=-6\\Test factors -3 and 2:\\-3*2=-6, -3+2=-1\\(x-3)(x+2)=0\\Use slide and divide with 2:\\(x-3/2)(x+2/2)=0\\=>\\(2x-3)(x+1)=0\\Set both equal to 0:\\x+1=0\\x=-1\\2x-3=0\\2x=3\\/2   /2\\x=3/2\\

Answer:

x=-1, 3/2

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\large\boxed{B.\ \left\{\begin{array}{ccc}2x+3y=7\\6x+y=11\end{array}\right}

Step-by-step explanation:

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After combining like terms and simplifying 1.17-0.07a+(-3.92a) we get 1.17-3.99a

Step-by-step explanation:

We need to combine like terms to simplify the expression:

1.17-0.07a+(-3.92a)

Like terms: The terms are like when they have same variable and same exponent.

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So, After combining like terms and simplifying 1.17-0.07a+(-3.92a) we get 1.17-3.99a

Keywords: Solving Expressions

Learn more about Solving Expressions at:

  • brainly.com/question/11207748
  • brainly.com/question/2154850
  • brainly.com/question/4279146

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