Suppose the cost of a unit failure is $200 and we need to maintain production for 3,000 hours. How much (in $) can we save if we

Question

suter [353]

3 years ago

15

Suppose the cost of a unit failure is $200 and we need to maintain production for 3,000 hours. How much (in $) can we save if we

improve the mean time between failures (mtbf) from 6 hours to 8 hours? Round the answer to two decimal places. G

Mathematics

1 answer:

Paha777 [63] · Answer 1 · 2022-04-04T10:06:36+03:00

Paha777 [63]3 years ago

3 0

The number of failures in 3000 hours with an MTBF of 6 hours is 500. When the MTBF is 8 hours, the number of failures drops to 375, a savings of the cost of 125 failures, or $25,000.