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3 years ago

14

Carl is conducting a survey for the school paper, he finds that 7 students have no pets, 15 have one pet, and 9 have at least tw

o pets. What is the experimental probability that the next student carl asks will not have a pet?

1 answer:

Elenna [48]3 years ago

4 0

I would say around 14%

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What is the correct value of z?<br> A. Z=12<br> B. Z=13<br> C. Z=10<br> D. Z=11

inna [77]

<h3>Answer: A) z = 12</h3>

==========================================

Work Shown:

RS = RT

2z-15 = 9

2z = 9+15

2z = 24

z = 24/2

z = 12

The reason why RS is equal to RT in the first equation is because we have an isosceles triangle. Recall that any isosceles triangle has exactly two sides the same length, and the opposite base angles are congruent to one another. The congruent angles are indicated with the single arcs.

In short: the base angles S and T are congruent, so the opposite sides RS and RT are the same length. This leads to RS = RT.

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2 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

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2 years ago

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Answer: one solution

this is all i know

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