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Arturiano [62]
3 years ago
8

Can you answer the question

Physics
1 answer:
Dominik [7]3 years ago
3 0
Can u show the whole question plz
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In this first example of constant accelerated motion, we will simply consider a car that is initially traveling along a straight
algol13

Answer:

v_{f} =25m/s

Explanation:

Kinematics equation for constant acceleration:

v_{f}  =v_{o} + at=15+2*5=25m/s

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2 years ago
Why does the moon exert a greater tidal influence than the sun?
andreyandreev [35.5K]
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when a cup of hot chocolate cools from 90c to 80c which of the following is happening to the molecules of the liquid
Murljashka [212]

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I think that the liquids molecules are slowing down. Hope this helps!

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3 years ago
Henry was given this cool toy for his birthday, he can use it to tell how fast someone is moving at that moment in time. The toy
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3 years ago
Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
soldi70 [24.7K]
Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}

GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} }  \approx 1.42\cdot 10^{12}m

3 0
3 years ago
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