Can you answer the question

What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?

Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

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5 0

1 year ago

Two children of about the same weight are playing at the playground. They both climb up to the top of a small tower. One slides

olya-2409 [2.1K]

Answer:

D

Explanation:

D) The overall work done by gravity is zero

This statement is correct .

If m be the mass of each of the children and h be the height of tower

work done by gravity on the boys in going up = - mgh

it is so because force applied by gravity = mg downwards and displacement

is upwards

work done will be negative = - mgh

Work done by gravity on boys when they come down = + mgh because both force and displacement are downwards .

Hence total work done = - mgh + mgh = 0.

The children will have same kinetic energy as the inclined surface is friction-less so no energy will be dissipated hence addition of energy to boys in both the cases will be same.

4 0

4 years ago

The man is walking with speed v1 = 1.35 m/s to the right when he trips over a small floor discontinuity. Estimate his angular ve

soldier1979 [14.2K]

Answer:

The angular velocity, $\omega = 1.05 rad/s$ clockwise

Explanation:

The mass of the man, m = 72 kg

The center of mass of the man will be at the middle of his body, particularly around his abdomen.

Height of the center of mass, h = 0.71 m

The speed of the man, v₁ = 1.35 m/s

Moment of inertia about the ankle joint, I = 66 kg/m²

Based on the principle of conservation of angular momentum (about the ankle joint):

Angular momentum before impact = Angular momentum after impact

Angular momentum before impact = -mv₁h

Angular momentum before impact = -(72 * 1.35 * 0.71)

Angular momentum before impact = -69.012 kg m²/s...............(1)

Angular momentum after impact = $I \omega$

Angular momentum after impact = $66 * \omega$ .................(2)

$66 \omega = -69.012\\\omega = -69.012/66\\\omega = -1.05 rad/s$

The angular velocity, $\omega = 1.05 rad/s$ clockwise

8 0

3 years ago

1. Through the law of gravity, Newton showed that two objects attracted by gravity actually orbit

____ [38]

The answer is “their common center of mass “

6 0

3 years ago

Does a thumb count as a finger

Lostsunrise [7]

A thumb does not count as a finger because it's said that we have FIVE digits on each hand, which includes the thumb.

6 0

3 years ago