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marusya05 [52]
3 years ago
8

Pirates drag a treasure chest to the left across a sandy beach. In which direction does the treasure chest experience a friction

al force, and why?
Physics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

Chest experiences the friction forces towards right

Explanation:

Friction forces can be defined as a force a body experiences when it is made to slide against the surface. Friction force always acts to stop the the body which is moving. To stop the body, it always acts in the opposite directions to the motion of the body. Therefore, if the treasure chest is dragged across a sandy beach to the left, the frictional forces will act in the right direction.

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True or false? If an element can form covalent bonds then it will never be involved in ionic bonding.
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Answer:

true

Explanation:

because the bonds in that element can only be shared but not transferred , but sometimes it depends on the element

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False . accelerating means to increase but moving at a constant speed means you stay the same .
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A car at the top of a ramp starts from rest and rolls to the bottom of the ramp, achieving a certain final speed. If you instead
zimovet [89]

Answer:

It must be 4 times high.

Explanation:

  • Assuming that the car can be treated as a point mass, and that the ramp is frictionless, the total mechanical energy must be conserved.
  • This means, that at any time, the following must be true:
  • ΔK (change in kinetic energy) = ΔU (change in gravitational potential energy)

⇒      m*g*h = \frac{1}{2} * m*v^{2}

  • Let's call v₁, to the final speed of the car, and h₁ to the height of the ramp.

       So, at the bottom of the ramp, all the gravitational potential energy

      must be equal to the kinetic energy of the car (Defining the bottom of

      the ramp as our zero reference for the gravitational potential energy):

       m*g*h_{1}  = \frac{1}{2} * m*v_{1} ^{2}  (1)

  • Now, let's do v₂ = 2* v₁
  • Replacing in (1) we get:

        m*g*h_{2}  = \frac{1}{2} * m*(2*v_{1}) ^{2} (2)

  • Dividing (2) by (1), and rearranging terms, we get:
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8 0
3 years ago
Two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference
777dan777 [17]

Two light waves will interfere constructively if the path-length difference between them is a whole number.

<h3>SUPERPOSITION</h3>

The principle of superposition state that, when two or more waves meet at a point, the resultant displacement at that point is equal to the sum of the displacements of the individual waves at that point.

Interference of waves can either be constructive, or destructive.

The two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number of wavelenght 1λ, 2λ, 3λ, 4λ etc

The equivalent phase differences between the waves will be 2\pi or 360 degrees, 4\pi or 720 degrees, 6\pi 1080 degrees etc

Therefore, the two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number.

Learn more about Interference here: brainly.com/question/25310724

8 0
2 years ago
Queremos un cilindro de simple efecto que utilice en su funcionamiento un volumen de aire a presión atmosférica de 13,122 litros
zhuklara [117]

Answer:

1) El diámetro es de aproximadamente 913,987 cm.

2) La fuerza del cilindro es 5576850 kgf

Explanation:

1) Los parámetros dados son;

El volumen del aire = 13,122 litros = 13122000 cm³

La presión de trabajo = 8.5 kgf / cm²

La longitud del cilindro = 20 cm.

Por lo tanto, tenemos;

El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²

r = √ (656100 / π) ≈ 456,994 cm

El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm

El diámetro ≈ 913,987 cm

2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo

∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf

La fuerza del cilindro = 5576850 kgf

3 0
3 years ago
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