a moving cart hits a spring, traveling at 5.0 m/s at the time of contact. at this instant the cart is motionless by how much is
1 answer:
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Explanation:
Value of the cross-sectional area is as follows.
A =
= 3.45
The given data is as follows.
Allowable stress = 14,500 psi
Shear stress = 7100 psi
Now, we will calculate maximum load from allowable stress as follows.
=
= 50025 lb
Now, maximum load from shear stress is as follows.
=
= 48990 lb
Hence, will be calculated as follows.
= 48990 lb
Thus, we can conclude that the maximum permissible load is 48990 lb.
We can calculate the acceleration of Cole due to friction using Newton's second law of motion:
where
is the frictional force (with a negative sign, since the force acts against the direction of motion) and m=100 kg is the mass of Cole and the sled. By rearranging the equation, we find
Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
where
is the final speed of the sled
is the initial speed
is the distance covered
By rearranging the equation, we find d:
where
Now we can use the following formula to calculate the distance covered by Cole and the sled before stopping:
where
By rearranging the equation, we find d: