F = 52000 N
m = 1060 kg
a= F/m = 52000 N/1060 kg = 49.0566 m/s^2
The specific heat of the unknown substance with a mass of 0.158kg is 0.5478 J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
The specific heat capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
- Q = quantity of heat absorbed (J)
- c = specific heat capacity (4.18 J/g°C)
- m = mass of substance
- ∆T = change in temperature (°C)
According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:
2510 = 158 × c × (61°C - 32°C)
2510 = 4582c
c = 2510 ÷ 4582
c = 0.5478 J/g°C
Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 0.5478 J/g°C.
Learn more about specific heat capacity at: brainly.com/question/2530523
Answer:
<em>The lighten travels 0.853 miles.</em>
Explanation:
Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.
v = 2x/t .......................................... Equation 1
making x the subject of the equation
x = vt/2........................................ Equation 2
Where v = velocity of sound in air, x = distance traveled by the sound, t = time
Given: v = 344 m/s t = 8 s
Substituting into equation 2
x = 344(8)/2
x = 1376 m.
x = 1376×0.00062 miles = 0.853 miles
<em>Thus the lighten travels 0.853 miles.</em>
Answer:
Explanation:
To plot the given forces of 0.8 N and 0.9 N. It is convenient to take
0.1 N as 1 unit in Graph
For example, 1 unit in the graph is 1 cm
then take 0.1 N equivalent to 1 cm
Answer:
2 m/s^2
Explanation:
from the question
v=15 m/s
t=7.5
a=?
from the first equation of motion
v=u+at
where,
v=final velocity
u=initial velocity
a=acceleration
t=time
from the question (u) will be zero because the body started at rest
v=u+at
15=(0)+a×7.5
15=7.5a
a=15/7.5
a=2 m/s^2
