Answer:
The volume of first and second compound are 9.15 ml and 10.85 ml.
Explanation:
Given that,
Density of graphite = 2.25 g/cm³
Volume of mixture = 20.0 mL
Density of first compound = 1.492 g/ml
Density of second compound = 2.890 g/ml
Let the volume of first mixture = x
The volume of second mixture = (20-x)....(I)
We need to calculate the volume of first compound
Using formula of density of mixture
![\rho=\dfrac{V_{1}\rho_{1}+V_{2}\rho_{2}}{V_{1}+V_{2}}](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7BV_%7B1%7D%5Crho_%7B1%7D%2BV_%7B2%7D%5Crho_%7B2%7D%7D%7BV_%7B1%7D%2BV_%7B2%7D%7D)
Where,
= volume of first compound
= volume of second compound
=density of first compound
= density of first compound
Put the volume into the formula
![2.25=\dfrac{x\times1.492+(20-x)\times2.890}{x+20-x}](https://tex.z-dn.net/?f=2.25%3D%5Cdfrac%7Bx%5Ctimes1.492%2B%2820-x%29%5Ctimes2.890%7D%7Bx%2B20-x%7D)
![45=1.492x+57.8-2.890x](https://tex.z-dn.net/?f=45%3D1.492x%2B57.8-2.890x)
![45-57.8=1.492x-2.890x](https://tex.z-dn.net/?f=45-57.8%3D1.492x-2.890x)
![12.8=1.398x](https://tex.z-dn.net/?f=12.8%3D1.398x)
![x=\dfrac{12.8}{1.398}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B12.8%7D%7B1.398%7D)
![x=9.15\ ml](https://tex.z-dn.net/?f=x%3D9.15%5C%20ml)
We need to calculate the volume of second compound
Using equation (I)
![V_{2}=20-x](https://tex.z-dn.net/?f=V_%7B2%7D%3D20-x)
Put the value of x
![V_{2}=20-9.15](https://tex.z-dn.net/?f=V_%7B2%7D%3D20-9.15)
![V_{2}=10.85\ ml](https://tex.z-dn.net/?f=V_%7B2%7D%3D10.85%5C%20ml)
Hence, The volume of first and second compound are 9.15 ml and 10.85 ml.