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Natali [406]
3 years ago
8

Please complete the sentence. A(n) __________________, a strainer, or a ladle can be used to separate the parts of a(n) ________

________ mixture.
Chemistry
2 answers:
Damm [24]3 years ago
7 0

A coffee filter, a strainer, or a ladle can be used to separate the parts of a heterogeneous mixture.

Akimi4 [234]3 years ago
5 0

In general, any type of filters or sieves can be used to separate heterogenous mixtures.


Therefore:

A(n) filter, a strainer or a ladle can be used to separate parts of a(n) heterogenous mixture.'



Hope it helped,



BioTeacher101

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State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3
Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

  • The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
  • The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

5 0
2 years ago
Read 2 more answers
What is the mass of 11.8 moles of water?
uysha [10]
First, find how many grams are in 1 mole of water.

For a hydrogen atom, there is about 1 gram per mole. For an oxygen atom, there are about 16 grams per mole.

In H2O, there are two hydrogen atoms and one oxygen atom. This means there are 18 grams in one mole of water. Multiply the mass in one mole by your number of moles.

18 x 11.8 = 212.4 grams

You have 212.4 grams of water.
4 0
3 years ago
How much heat is needed to raise the temperature of 55.0 g sample of water by 65.0 oC.
sveticcg [70]

Answer: 14943.5 J

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass of water = 55.0g

C = 4.18 J/g°C

Φ = 65.0°C

Then, Q = MCΦ

Q = 55.0g x 4.18 J/g°C x 65.0°C

Q = 14943.5 J

Thus, 14943.5 joules of heat is needed to raise the temperature of water.

3 0
3 years ago
Read 2 more answers
If you were going to graphically determine the enthalpy of vaporization, δhvap, for this liquid, what points would you plot
Klio2033 [76]
It depends on what type of graph you have. The easiest would be using a H-T diagram. Enthalpy of vaporization is the physical change from liquid to vapor. It occurs at a constant pressure and a constant temperature. As shown in the picture, 1 point is drawn on the subcooled liquid, and another point of the saturated vapor isothermal line. Now, the difference between those two points is the value for the enthalpy of vaporization of water.

8 0
4 years ago
1.) Which line is pointing to the axon terminals?
Naily [24]

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

4 0
2 years ago
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