This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:

where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:


Therefore, the specific heat of a material is, 0.137 J/g.K
Answer:
i
b because it says it in the question
False, although the air is moving in an equilibrium us normal humans can not see the air actually moving. So it is false.
Answer:
a fruit and oatmeal bar contains 142000 calories.
A nutritional calorie, or kilocalorie, is equal to 1000 calories.
E = 142 kcal · 1000 cal/kcal.
E = 142 000 cal.
Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
One small calorie is approximately 4.2 joules.
A calorie is a unit of energy.
Explanation:
hope it helps :)