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Norma-Jean [14]
3 years ago
8

Interstellar clouds are primarily composed of nitrogen and oxygen. true or false?

Chemistry
2 answers:
astra-53 [7]3 years ago
7 0

Answer:

The statement is false

Explanation:

Interstellar clouds are not primarily composed of nitrogen and oxygen. Interstellar clouds are generally an made up of gas, plasma, and dust in our and other galaxies.

sesenic [268]3 years ago
3 0

Answer: False

Explanation:

An interstellar cloud can be defined as the accumulation of gas, plasma and dust in our galaxy or other galaxy.

The composition of interstellar clouds are determined by studying the electromagnetic radiation that is received by radio waves, gamma rays on the electromagnetic spectrum.

When The electromagnetic radiations was studied then organic compounds like vinyl chloride and methanol which was not expected.

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Weathering is the name given to the process of breaking-down rocks at Earth's surface. This is accomplished due to the exposure to oxygen through the process of oxidation and to the exposure to water in its various forms (liquid, solid, & gas). ... Water is the primary agent for mechanical weathering.
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3 years ago
How can some of the difficulties caused by the Down Syndrome be over come?
Salsk061 [2.6K]
There is no single, standard treatment for down syndrome.
4 0
3 years ago
Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th
Black_prince [1.1K]

Answer:

K_{goal}=1.793*10^{-33}

Explanation:

N2(g)+O2(g)⇌2NO(g), K_1 = 4.10*10^{-31}

N2(g)+2H2(g)⇌N2H4(g), K_2 = 7.40*10^{-26}

2H2O(g)⇌2H2(g)+O2(g), K_3 = 1.06*10^{-10}

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g)                     Eq (1)

Equilibrium constant for Eq (1) is K_1*K_3*K_3

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g)                       Eq (2)  

Equilibrium constant for Eq (2) is (K_1*K_3*K_3)^{1/2}

Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}

7 0
3 years ago
2. How many grams of zinc will be formed if 32.0 g of copper reacts with zinc nitrate? Copper(I)nitrate is the other product.
Yakvenalex [24]

Answer:

16.46 g.

Explanation:

  • It is a stichiometry problem.
  • We should write the balance equation of the mentioned chemical reaction:

<em>2Cu + Zn(NO₃)₂ → Zn + 2Cu(NO₃).</em>

  • It is clear that 2.0 moles of Cu reacts with 1.0 mole of Zn(NO₃)₂ to produce 1.0 mole of Zn and 2.0 moles of Cu(NO₃).
  • We need to calculate the number of moles of the reacted Cu (32.0 g) using the relation:

<em>n = mass / molar mass</em>

  • The no. of moles of Cu = mass / atomic mass = (32.0 g) / (63.546 g/mol) = 0.503 mol.

<u><em>Using cross multiplication:</em></u>

2.0 moles of Cu produces → 1.0 mole of Zn, from the stichiometry.

0.503 mole of Cu produces → ??? mole of Zn.

  • The no. of moles of Zn produced = (1.0 mol)(0.503 mol) / (2.0 mol) = 0.2517 mol.

∴ The grams of Zn produced = no. of moles x atomic mass of Zn = (0.2517 mol)(65.38 g/mol) = 16.46 g.

3 0
3 years ago
How many moles of O2 are needed to burn 2.56 moles of CH3OH?
lukranit [14]

Answer:

n_{O_2}=3.84molO_2

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2

Best regards!

6 0
3 years ago
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