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NemiM [27]
1 year ago
14

Element c has a strong emmission aound 450nm Does this emmission line reprosent a lower of higher emergy line at 627 nm?

Chemistry
1 answer:
Julli [10]1 year ago
5 0

It  respresents the higher energy level than 627nm .

<h3>What is a emission line ? </h3>

Emission lines are the glowing hot gas emits lines of light whereas absorption line  refers to the tendency of  cool atmospheric gas to absorb the same line of light.Some lights produce dark band when the light passes through gas in the atmosphere . There are two line spectrum  and absorption.

 spectrum is an excitement of  electrons from lower to higher energy levels and when it comes back it releases energy in the terms of colourful lights .

It represents the  higher energy levels than 627nm because Energy is inversly proportional to wavelength .

to learn more about Emission lines click here

 brainly.com/question/28184999

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What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

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3 0
1 year ago
What is the rate constant of a reaction if rate = 1 x 10-2 (mol/L)/s, [A] is 2 M,
boyakko [2]

The rate constant of a reaction : 8.3 x 10⁻⁴

<h3>Further explanation</h3>

Given

rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M,  [B] is 3 M, m = 2, and n = 1

Required

the rate constant

Solution

For aA + bB ⇒ C + D

Reaction rate can be formulated:

\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}

the rate constant : k =

\tt k=\dfrac{rate}{[A]^m[B]^n}\\\\k=\dfrac{1.10^{-2}}{2^2\times 3^1}\\\\k=8.3\times 10^{-4}

8 0
2 years ago
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Help ASAP I will mark brainliest for the correct answer !!!⚡️✨
Artist 52 [7]

Answer:

10623 km

Explanation:

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3 0
3 years ago
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Angelina_Jolie [31]

Answer : B) In step 2, there was a chemical change which was observed in sugar.

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Therefore only in B step 2 there was a chemical change that was observed.

4 0
3 years ago
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What is the primary difference between a molecule and a compound?
Korvikt [17]
The Answer is A

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