Answer:
The answer to your question is: V2 = 1.94 l
Explanation:
Data
V1 = 2.42 l
T1 = 25°C
P1 = 1 atm
V2 = ?
T2 = 25 -11 = 14°C
P2 = 1(0.7) = 0.7 atm
Formula
P1V1/T1 = P2V2/T2
Clear V2 from the equation
V2 = P1V1T2/ P2T1
V2 = (1)((2.42)(14) / (0.7)(25)
V2 = 33.88 / 17.5
V2 = 1.94 l
Answer:
Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.
Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.
Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.
Explanation:
1 mole of any compound contains 6.023 × 10²³ molecules.
molecular weight of NaCl is 23 + 35.5 = 58.5 g.
so, 58.5 grams of NaCl makes 1 mole
⇒ 14.5 g of NaCl =
= 0.248 moles.
⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules
= 1.49 × 10²³ molecules.
And 1 molecule contains 1 Na ion and 1 Cl ion.
⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.
⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.
Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.