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Tpy6a [65]
3 years ago
11

The mean percentage of a population of people eating out at least once a week is 57%, with a standard deviation of 3.5%. Assume

that a sample size of 40 people was surveyed from the population an infinite number of times. In which interval will 95% of the sample means occur?
Mathematics
1 answer:
Serhud [2]3 years ago
6 0
95% C.I. = mean + or - 1.96(standard deviation / sqrt(sample size))
95% C.I. = 57 + or - 1.96(3.5/sqrt(40) = 57 + or - 1.085 = 57 - 1.085 to 57 + 1.085 = 55.92 to 58.09

Therefore, 95% of the mean will occur in the interval 55.92 to 58.09
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Worth 17 points! Help me please!!! Look in the picture
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Answer:

Part A

1. After 4 weeks of work, Jeremy has saved <u>300</u>

2. Jeremy worked <u>8</u> weeks in order to save $600

3. For every one week of work, Jeremy saved <u>75</u> dollars

4. If Jeremy works 15 weeks, then he can expect to save <u>1,125</u> dollars

Part B

1. Saeed orders 15 meals and his total cost of delivery is <u>$24</u>

2. Saeed paid $32 to have <u>20</u> meals delivered

3. For every meal delivered, Saeed is charged <u>$1.6</u>

4. If Saeed pays $19.20 in delivery fees then he ordered <u>12</u> meals

Step-by-step explanation:

Part A

The given graph gives the proportional relationship between total amount saved and the number of weeks worked

1. Reading from the graph, at the point where the vertical line from point 4 touches the line of the graph, an horizontal line to the vertical y-axis touches the y-axis at 300

Therefore;

After 4 weeks of work, Jeremy has saved <u>300</u>

2. The point where an horizontal line from point 600 on the vertical y-axis touches the line of the graph, a vertical line drawn to the horizontal, x-axis touches the x-axis at 8

Therefore;

Jeremy worked <u>8</u> weeks in order to save $600.

3. The rate of change of the amount saved to the number of weeks worked, 'm', for the given proportional relationship (straight line relationship, passing through the origin) is given as follows;

Rate of change, m = Constant = y/x

∴ Rate of change of the amount saved to the number of weeks worked = (300-0)/(4 weeks- 0 week) = 75/week

Therefore;

For every one week of work, Jeremy saved <u>75</u> dollars

4. The amount Jeremy would have saved in 15 weeks, 'A', is given as follows;

A = m × n

Where;

m = The rate of change of the amount saved to the number of weeks worked = 75/week

n = The number of weeks worked

∴ A = 75/week × 15 = $1,125

Therefore;

If Jeremy works 15 weeks, then he can expect to save <u>1,125</u> dollars

Part B

From the graph, we have;

1. From the graph there is a proportional relationship between the total cost of delivery and the number of meals

At the point a vertical line drawn to the line of the graph from 15 on the horizontal axis (number of meals), a horizontal line drawn to the vertical y-axis touches the y-axis at 24

Therefore;

1. Saeed orders 15 meals and his total cost of delivery is <u>$24</u>

2. From the point where the horizontal line from 32 on the vertical axis touches the linear graph of the relationship between the total cost of delivery and the number of meals, a vertical line drawn down to the horizonal axis touches the horizontal x-axis at 20

Therefore;

Saeed paid $32 to have <u>20</u> meals delivered

3. The rate of change of the total cost of delivery to the number of meals, 'm', is given as follows;

m = y/x (for proportional relationships)

Taking any corresponding 'x' and y-values

m = 16/10 = 32/20 = 24/15 = 1.6 Dollars/meal

Therefore;

For every meal delivered, Saeed is charged <u>$1.6</u>

4. From m = y/x = 1.6

When y = $19.20

x = y/m = $19.20/($1.6/meal) = 12 meals

Therefore;

If Saeed pays $19.20 in delivery fees then he ordered <u>12</u> meals.

3 0
3 years ago
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