The weigth of a body decrease in a coal mine why?

Physics

2 answers:

pychu [463]3 years ago

5 0

Answer

Gravitational force is between two object caused by energy in mass. Here when you are in a mine the radius of the earth in case of calculating gravity is reduced to the length between you and the center.

This means the mass of earth is decreasing even though the distance is decreasing. Relative to the decrease in distance squared the decrease in the mass of the second object(earth) is more. As a result your weight decreases.

posledela3 years ago

5 0

Answer:

Explanation: that means as you descend into the earth, all of the mass in all the shells above you gets canceled. If the centre of the earth were not molten iron, but instead hollowed out, you would be weightless inside.

The physics problem is actually a little more general. It applies to inverse square force laws such as the electrical force. So if you put an electron inside a positively or negatively charged sphere, it will also have a net force on it of zero.

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Halleys comet has period of 75.3 years. Using Kepler’s third law, find it’s semimajor axis expressed in astronomical units?

natta225 [31]

Answer: 17.83 AU

Explanation:

According to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. 

$T^{2}\propto a^{3}$ (1)

Talking in general, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite, comet) orbiting a greater body in space with the size $a$ of its orbit.

However, if $T$ is measured in years, and $a$ is measured in astronomical units (equivalent to the distance between the Sun and the Earth: $1AU=1.5(10)^{8}km$ ), equation (1) becomes: