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Ira Lisetskai [31]
2 years ago
13

If 56.5 m3 of a gas are collected at a pressure of 455 mm Hg, what volume will the gas occupy if the pressure is changed to 632

mm Hg? *
Physics
1 answer:
ExtremeBDS [4]2 years ago
4 0

Assuming ideal conditions, Boyle's law says that

<em>P₁ V₁ </em>= <em>P₂</em> <em>V₂</em>

where <em>P₁ </em>and <em>V₁</em> are the initial pressure and temperature, respectively, and <em>P₂</em> and <em>V₂</em> are the final pressure and temperature.

So you have

(455 mm Hg) (56.5 m³) = (632 mm Hg) <em>V₂</em>

==>   <em>V₂</em> = (455 mm Hg) (56.5 m³) / (632 mm Hg) ≈ 40.7 m³

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