All categories

3 years ago

Diana hangs a lead cylinder with a force of 12 N from a model bridge.

Physics

1 answer:

vova2212 [387]3 years ago

7 0

The answer would be A and I’m pretty sure of thta

You might be interested in

HEL ME PLEASE I HAVE NO IDEA OF WHAT TO DO!!!!!!

Dahasolnce [82]

Answer:

b, the fastest the car has traveled out of those options is 4-5 seconds.

Explanation:

3 0

3 years ago

Read 2 more answers

When water dissolves salts, the negative ends of the water molecules are attracted to the negative ions of the salt.

neonofarm [45]

The response for your quetion is true

4 0

3 years ago

A disc on a frictionless axle, starting from rest (0 rpm) can spin up to a rotation rate of 3820 rpm in a period of 2 seconds. (

Eddi Din [679]

Answer:

1000 Nm

2000 Nm

1.00007 seconds

Explanation:

I = Moment of inertia = 5 kgm²

$\alpha$ = Angular acceleration

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

t = Time taken

Torque is given by

$\tau=I\alpha\\\Rightarrow \tau=5\times 200\\\Rightarrow \tau=1000\ Nm$

The torque of the disc would be 1000 Nm

If $\alpha=400\ rad/s^2$

$\tau=I\alpha\\\Rightarrow \tau=5\times 400\\\Rightarrow \tau=2000\ Nm$

The torque of the disc would be 2000 Nm

From equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{3820\times \frac{2\pi}{60}-0}{400}\\\Rightarrow t=1.00007\ s$

It would take 1.00007 seconds to reach 3820 rpm

6 0

4 years ago

Which of these is not a proper hand washing step

aleksandrvk [35]

Which of what? Apologies please list the following so I can help.

8 0

3 years ago

A mass m = 0.6 kg is released from rest at the top edge of a hemispherical bowl with radius = 1.1 meters. The mass then slides w

Aneli [31]

Answer:

The angle is $\theta = 36.24 ^o$

Explanation:

From the question we are told that

The mass is $m = 0.6 \ kg$

The radius is $r = 1.1 \ m$

The speed is $v = 3.57 \ m /s$

According to the law of energy conservation

The potential energy of the mass at the top is equal to the kinetic energy at the bottom i.e

$m * g * h = \frac{1}{2} * m * v^2$

=> $h = \frac{1}{2 g } * v^2$

Here h is the vertical distance traveled by the mass which is also mathematically represented as

$h = r * sin (\theta )$

$\theta = sin ^{-1} [ \frac{1}{2* g* r } * v^2]$

substituting values

$\theta = sin ^{-1} [ \frac{1}{2* 9.8* 1.1 } * (3.57)^2]$

$\theta = 36.24 ^o$

3 0

4 years ago