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kogti [31]
2 years ago
5

Why do cars stay in motion.

Physics
2 answers:
Oksi-84 [34.3K]2 years ago
7 0

Answer:

it stays in motion

Explanation:

An object in motion will stay in motion until a force acts on it

liubo4ka [24]2 years ago
6 0

Answer:

Friction is the resistance to motion created by two objects moving against each other. Friction creates heat. Unless acted on by a force, objects in motion tend to stay in motion and objects at rest remain at rest.

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At what water temperature will additional heat energy need to be added before the temperature will change again?
Lostsunrise [7]
That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)<span />

6 0
3 years ago
Why the reflected rays for a rough surface do not result in the formation of an image.
Oksana_A [137]

Answer:

this is because the light rays get reflected irregularly

Explanation:

8 0
2 years ago
Steve does 80 J of work to a rope threaded through a pulley and attached to a crate of anvils. The tension of the rope is 10 N a
Ivahew [28]

Answer:

The Answer is (B)

Explanation:

6 0
3 years ago
Read 2 more answers
If viewed at the correct time and in the right conditions, asteroids, comets, and meteors are all visible to the nked eye.
UkoKoshka [18]

Answer:

True

Explanation:

If it is at right conditions and correct time (night time most likely) they will all be visible

8 0
1 year ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
jeyben [28]

Answer:

λ₁ = 2.50 10⁻² m,   λ₂ = 1.66 10⁻² m  

Explanation:

Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.

Let's calculate the wavelength for the two extreme frequencies of this band

wavelength and frequency are related

         c = λ f

          λ = c / f

f₁ = 12 GHz = 12 10⁹ Hz

          λ₁ = 3 10⁸ /12 10⁹

           λ₁ = 2.50 10⁻² m

f₂ = 18 GHz = 18 10⁹ Hz

          λ₂ = 3 10⁸ /18 10⁹

          λ₂ = 1.66 10⁻² m

Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures

8 0
3 years ago
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