All categories

3 years ago

Why do cars stay in motion.

Physics

2 answers:

Oksi-84 [34.3K]3 years ago

7 0

Answer:

it stays in motion

Explanation:

An object in motion will stay in motion until a force acts on it

liubo4ka [24]3 years ago

6 0

Answer:

Friction is the resistance to motion created by two objects moving against each other. Friction creates heat. Unless acted on by a force, objects in motion tend to stay in motion and objects at rest remain at rest.

You might be interested in

An airplane accelerates from rest down a runway at 3.20 m/s2 for 32.8 seconds until it lifts off the ground. Determine the dista

vagabundo [1.1K]

Answer:

s=1721.344m ,v=104.96m/s.

Explanation:

using thr equation of motion;

$s=ut+\frac{1}{2}at^{2}$

u=0, plane starts from rest,

$s=\frac{1}{2}at^{2}$

$a=3.2m/s^{2}, t=32.8s \\ s=\frac{1}{2}*3.2*32.8^{2}$

s=1721.344m

v=u+at

v=0 +3.2*32.8

v=104.96m/s

8 0

3 years ago

A hockey player strikes a puck that is initially at rest. The force exerted by the stick on the puck is 975 N, and the stick is

Anna007 [38]

Explanation:

Given that,

The force exerted by the stick on the puck is 975 N

The stick is in contact with the puck for 0.0049 s

Initial speed of the puck, u = 0 (at rest)

(a) We need to find the impulse imparted by the stick to the puck.

Impulse = Force × time

J = 4.7775 kg-m/s

(b) Mass of the puck, m = 1.76 kg

We need to find the speed of the puck just after it leaves the hockey stick.

Let the speed be v.

As impulse is equal to the change in momentum.

$J=m(v-u)\\\\4.7775=1.67(v-0)\\\\v=\dfrac{4.7775}{1.67}\\\\v=2.86\ m/s$

So, when the puck leaves the hockey stick its speed is 2.86 m/s.

8 0

3 years ago

If the frequency of the wave is 100 hz, what is the period of the wave?.

Cerrena [4.2K]

Answer:
Time= 1/frequency
=1/100
=0.01
Explanation:

3 0

3 years ago

A light source shines light consisting of two wavelengths, λ1 = 540 nm (green) and λ2 = 450 nm (blue), on two slits separated by

densk [106]

Answer:

The maximun distance is $z_1 = z_2 = 0.0138m$

Explanation:

From the question we are told that

The wavelength are $\lambda _ 1 = 540nm (green) = 540 *10^{-9}m$

$\lambda_2 = 450nm(blue) = 450 *10^{-9}m$

The distance of seperation of the two slit is $d = 0.180mm = 0.180 *10^{-3}m$

The distance from the screen is $D = 1.53m$

Generally the distance of the bright fringe to the center of the screen is mathematically represented as

$z = \frac{m \lambda D}{d}$

Where m is the order of the fringe

For the first wavelength we have

$z_1 = \frac{m_1 (549 *10^{-9} * (1.53))}{0.180*10^{-3}}$

$z_1=0.00459m_1 m$

$z_1= 4.6*10^{-3}m_1 m ----(1)$

For the second wavelength we have

$z_2 = m_2 \frac{450*10^{-9} * 1.53 }{0.180*10^{-3}}$

$z_2 = 0.003825m_2$

$z_2 = 3.825 *10^{-3} m_2 m$ ----(2)

From the question we are told that the two sides coincides with one another so

$zy_1 =z_2$

$4.6*10^{-3}m_1 m = 3.825 *10^{-3} m_2 m$

$\frac{m_1}{m_2} = \frac{3.825 *10^{-3}}{4.6*10^{-3}}$

Hence for this equation to be solved

$m_1 = 3$

and $m_2 = 4$

Substituting this into the equation

$z_1 = z_2 = 3 * 4.6*10^{-3} = 4* 3.825*10^{-3}$

Hence $z_1 = z_2 = 0.0138m$

7 0

3 years ago

The main purpose of the turbine in the turbojet engine is to

AnnZ [28]

<span>The correct answer is A. drive the compressor. It's not D because the compressor compresses it, not the turbine. The temperature and the velocity of gasses are unrelated to this. There are in fact two turbines, and the first one gets power from exhaustion, which is then used to power to turbine in the turbojet that is used to drive the compressor. This is how turbojets commonly work.</span>

8 0

3 years ago