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Roman55 [17]
3 years ago
9

In physics grade 10 number 8 in the pic how do we do it thanks in advance

Physics
1 answer:
Rom4ik [11]3 years ago
5 0
Hope this helps you.

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A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
SpyIntel [72]

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

E = \frac{hc}{\lambda}\\\\

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\

<u>n = 4 x 10¹⁸ photons</u>

8 0
3 years ago
A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between
Oduvanchick [21]

Answer:

Net electric field, E_{net}=91406.24\ N/C

Explanation:

Given that,

Charge 1, q_1=7.5\ nC=7.5\times 10^{-9}\ C

Charge 2, q_2=-2.9\ nC=-2.9\times 10^{-9}\ C

distance, d = 3.2 cm = 0.032 m

Electric field due to charge 1 is given by :

E_1=\dfrac{kq_1}{r^2}

E_1=\dfrac{9\times 10^9\times 7.5\times 10^{-9}}{(0.032)^2}

E_1=65917.96\ N/C

Electric field due to charge 2 is given by :

E_2=\dfrac{kq_2}{r^2}

E_2=\dfrac{9\times 10^9\times 2.9\times 10^{-9}}{(0.032)^2}

E_2=25488.28\ N/C

The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :

E_{net}=E_1+E_2

E_{net}=65917.96+25488.28

E_{net}=91406.24\ N/C

So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.

3 0
4 years ago
You've learned about simple circuits and resistors at this point. So, let's talk about how we can power different circuits. Supp
DIA [1.3K]

Answer:

Explanation:

Total resistance of 2 bulb in series

= 100 +100 = 200 ohm

current in each bulb

= 9/200 = .045 A

In case of parallel combination of bulb

total resistance

= 100 x 100 / (100+100)

50 ohm

current in the main circuit

= 9 / 50 A

current in each bulb

= 9 / (2 x 50)

.09

So in the second case current is more , hence heat generated too will be more . So brightness too will be more.

First set (  in  series ) will be dimmer.

3 0
3 years ago
If a car has a mass of 1,000 kilograms, and a velocity of 35 m/s. What is its momentum?
fenix001 [56]

\vec{p}=m\vec{v}\\p = 1000 * 35=35000[\frac{kg*m}{s}]

7 0
3 years ago
In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is
goldfiish [28.3K]

In the opposite figure, the work done by the force F to push the box upwards from the ground to the top of the inclined plane is 600 J.Option c is correct.

<h3>What is work done?</h3>

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

The displacement value from the triangle is;

\rm sin 30^0 = \frac{P}{H} \\\\ H=S =\frac{3 \ m}{sin 30^0} \\\\ S = 6\ m

The work done is found as ;

\rm W= Fd \\\\ W = 100  \ N \times 6 \\\\ W= 600 \ J

The force F in the opposing figure does 600 J of effort to lift the box from the ground to the top of the inclined plane.

Hence option c is correct.

To learn more about the work done refer to the link;

brainly.com/question/3902440

#SPJ1

4 0
2 years ago
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