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3 years ago

1.34 milligrams is the same as _ kg and _g.

Chemistry

2 answers:

agasfer [191]3 years ago

7 0

1.34 milligrams in kg is C. 0.00000134 whereas 1.34 milligrams in gm is 0.00134.

Karolina [17]3 years ago

3 0

Answer C is for kg and but it's .00134 for grams

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sashaice [31]

Answer:d

Explanation:

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3 years ago

Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g

Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒ $Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}$

On substituting the values, we get

⇒ $0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}$

⇒ $Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}$

⇒ $=1.5\times 10^{-3}$

hence,

⇒ $Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}$

On substituting the values, we get

⇒ $1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}$

⇒ $Mass \ of \ acid=1.5\times 10^{-3}\times 400$

⇒ $=0.60 \ g$

8 0

3 years ago

Here is my question only answer if you understand this question

sasho [114]

1- false
2- true
3- true
4- false
5- true
6- false
7- true
8- true
9- true
10- false

Hope it helps :)

8 0

3 years ago

For the reaction represented by the equation Fe + H2O ® Fe2O3 + H2, how many moles of iron(III) oxide are produced from 285 g of

schepotkina [342]

Balanced equation: 2Fe + 3H2O → Fe2O3 +3H2

Convert g to mols:

285/55.845 = 5.1034 mols

Mole ratio of Iron and Iron (III) Oxide: 2:1

5.1034/2 = 2.5517 mols

8 0

2 years ago

what order does covalent bond, dipole-dipole, hydrogen bond, ionic bond, metalic bond, and london dispersion bond for strength?

jarptica [38.1K]

Answer:The major types of solids are ionic, molecular, covalent, and metallic. ... (network) , or metallic, where the general order of increasing strength of interactions. ... In ionic and molecular solids, there are no chemical bonds between the ... by dipole –dipole interactions, London dispersion forces, or hydrogen ...

Explanation:

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7 0

3 years ago

1.34 milligrams is the same as _____ kg and _____g.

1.34 milligrams is the same as _ kg and _g.