The solution would be like this for this specific problem:
Given:
pH of a 0.55 M hypobromous
acid (HBrO) at 25.0 °C = 4.48
[H+] = 10^-4.48 = 3.31 x
10^-5 M = [BrO-] <span>
Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>
To add, Hypobromous Acid does not require acid
adjustment, which is necessary for chlorine-based product and is stable and
effective in pH ranges of 5-9.<span>
</span>Hypobromous Acid combines with organic
compounds to form a bromamine. Chlorine also combines with the same organic
compounds to form a chloramine. <span>It is also
one of the least expensive intervention antimicrobial compounds available.</span>
Answer:
there are two significant figures is the number 8400
Explanation:
Answer:
Approximately 
.
Explanation:
Make use of the molar mass data (
) to calculate the number of moles of molecules in that 
of 
:
.
Make sure that the equation for this reaction is balanced.
Coefficient of in this equation: 
.
Coefficient of 
in this equation: .
In other words, for every two moles of that this reaction consumes, two moles of would be produced.
Equivalently, for every mole of that this reaction consumes, one mole of would be produced.
Hence the ratio: 
.
Apply this ratio to find the number of moles of that this reaction would have produced:
.
Just like how heat moves from a region of higher
temperature to a region of lower temperature, molecules also tend to move from
a region of higher concentration to a region of lower concentration. This is
called natural diffusion and is naturally happening to reach stability.
Answer:
The number before any molecular formula applies to the entire formula. So here you have five molecules of water with two hydrogen atoms and one oxygen atom per molecule. Thus you have ten hydrogen atoms and five oxygen atoms in total.
