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Anton [14]
3 years ago
7

Which of the following represent a mixture?

Chemistry
1 answer:
7nadin3 [17]3 years ago
6 0
The answer is B NaCI solid
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A pharmaceutical company claimed that experiments showed that its drug could effectively reduce the growth of cancer cells by 35
BaLLatris [955]

Answer :  The labs were unable to reproduce the pharmaceutical company’s data.

Explanation : Any scientific claim must have reproducible experimental data. In this case, when the pharmaceutical company has the claim of reducing the cancer growth cells by 35% then by using the same manufacturing procedure for the drug and lab should be able to get this result. But they failed to match up with the results which clearly indicates that the labs were not able to produce the same results and hence they concluded that the pharmaceutical company's claims were invalid.

4 0
3 years ago
Read 2 more answers
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
For the reaction HNO3 + Mg(OH)2→ Mg(NO3)2 + H2O, how many grams of magnesium nitrate are produced from 8.00 mol of nitric acid,
ollegr [7]

Answer:

tha mass of magnesium nitrate is 592g

Explanation:

from a balanced chemical equation

2HNO3 + Mg(OH)2→ Mg(NO3)2 + 2H2O

2 mol of nitric acid is equivalent to 1 mol of magnesium nitrate. then 8 mol of nitric acid will be equivalent to 4 mol of magnesium nitrate.

6 0
2 years ago
Read 2 more answers
Consider the chemical equation below.
Aleks [24]
I would say A but then again im not too sure so hope that makes it easier to somehow
6 0
3 years ago
Read 2 more answers
Krypton-79 has a half-life of 35 hours. how many half-lives have passed after 105 hours?
Nookie1986 [14]
The number of half -lives that has passed after 105  hours  for krypton-79 that has  half-life of 35 hours is calculated as below

if 1 half life = 35 hours

what about 105 hours = ? half-lives

= (1 half life  x105  hours) /35 hours = 3 half-lives  has passed after 105 hours
6 0
3 years ago
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