Answer:
85.6 g
Explanation:
Step 1: Write the balanced combustion equation
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Step 2: Calculate the moles corresponding to 140 g of H₂O
The molar mass of H₂O is 18.02 g/mol.
140 g × 1 mol/18.02 g = 7.77 mol
Step 3: Calculate the moles of C₃H₈ needed to produce 7.77 moles of H₂O
The molar ratio of C₃H₈ to H₂O is 1:4. The moles of C₃H₈ needed are 1/4 × 7.77 mol = 1.94 mol.
Step 4: Calculate the mass corresponding to 1.94 moles of C₃H₈
The molar mass of C₃H₈ is 44.10 g/mol.
1.94 mol × 44.10 g/mol = 85.6 g
I think its c ,,,,,,,,,,,,,,,,,,,,,,,,
Answer:
d
Explanation:
Firstly, we need to see the theoretical mole ratio between nitrogen and ammonia from the balanced chemical equation. This is 1 to 2. One mole of nitrogen yielded two moles of ammonia.
At STP, one mole of a gas occupies a volume of 22.4, hence we need to know the volume occupied by a volume of 44.8L of ammonia. This is equal to 44.8/2 = 2 moles
Now we have seen the actual number of moles of ammonia yielded. Since this is the same as the theoretical, it means that only one mole of nitrogen was also used up.
Since it is one mole, the volume at STP is thus 22.4L
The object will speed up and start to spin in different directions.
