solution:
A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg
Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.
Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.
Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.
Br2 because it is non polar and so is CCl4 and like molecules dissolve like molecules therefore Br2 will dissolve in CCl4
Okay so,
1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced
2) mRNA leaves the cell and joins with a ribosome
3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished
4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)
Hope this helps :)
