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Nikolay [14]
2 years ago
5

What happens to the ionizing rate if the steps of ionizing polyprotic acid increases?

Chemistry
2 answers:
Tanzania [10]2 years ago
5 0

Answer:

<h3>An acid that contains more than one ionizable proton is a polyprotic acid. The protons of these acids ionize in steps. The differences in the acid ionization constants for the successive ionizations of the protons in a polyprotic acid usually vary by roughly five orders of magnitude.</h3>
zhenek [66]2 years ago
4 0

Answer:

What happens to the ionizing rate if the steps of ionizing polyprotic acid increases? Well they have this stepwise ionization process occurs for all polyprotic acids

Explanation:

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First, calculate for the mass of the aqueous solution by multiplying the given volume (in mL) by the density (in g/mL). In mathematical equation, that is,

        m = ρV

where m is mass, ρ is density, and V is volume. Substituting the known values,

      m = (1.03 g/mL)(250 mL) = 257.5 g

To get the concentration in ppm, divide the given mass of methanol by the mass of the solution. Note that the parts-per million (ppm) is equal to mass of solute in milligram(mg) divided by the mass of solution in kilogram (kg)

      C (in ppm) = (1.56 x 10^-6 g)(1000 mg/1 g)   / (257.5 g)(1 kg/1000 g)

Simplifying,
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<em>Answer: 0.00606 ppm</em>
     
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