To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).
To start, we find the square of the distance between x1 and x2 and y1 and y2. The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.
Now we square 2 and 7 and add them together to get 4 + 49 = 53.
The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
Answer:
y=2x+7
Step-by-step explanation:
A linear equation is typically organized in the form y=mx+b, where m is the slope of the line and b is the y-intercept (the y-coordinate of the point on the line that crosses the y-axis).
Parallel lines <em>always</em> have the same slope. When we examine the given equation, y=2x+6, we can identify immediately that 2 is in the place of m, the slope. This means that the slope of the line we're trying to solve for is also 2. So far, our equation looks like this:
y=2x+b
The last thing we need to calculate is b, the y-intercept. We can do this by plugging in the given point (-1,5) as x and y.
y=2x+b
5=2(-1)+b
5=-2+b
Add 2 to both sides to isolate b
5+2=-2+b+2
7=b
Now that we know b, we plug that into our original equation and now we have a final equation of:
y=2x+7
I hope this helps!
The answer is 11 so C=11.
