Answer:
15.7079
Step-by-step explanation:
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
Answer:
(y - 1)(5y - 2)
Solution:
Factor:
2 - y(7 - 5y)
Apply the Distributive Property:
2 - 7y + 5y²
Reorder the expression:
5y² - 7y + 2
Rewrite the term:
5y² - 5y - 2y + 2
Regroup terms into two proportional parts:
(5y² - 5y) + ( -2y + 2)
Factor Greatest Common Factors out:
5y(y - 1) - 2(y - 1)
(y - 1)(5y - 2)
The sine has a range -1 to +1 so y goes from 1+2(-1) to 1+2(1) = -1 to 3
Range: -1 ≤ y ≤ 3
Answer: my Face bone A** tight cheerio from last night hit them with that good good make him want to act right Thank me and brain
List to me
Step-by-step explanation:
