<h3>
Answer:</h3>
0.5 moles/L or 0.5 M
<h3>
Explanation:</h3>
- Molarity is the concentration of a solution in moles per liter.
- It is calculated by;
Molarity = Number of moles ÷ Volume
In this case;
Volume = 125 mL
Mass of sodium nitrate = 5.31 g
We are required to calculate the molarity of sodium nitrate
<h3>Step 1: Calculate the number of moles of sodium nitrate </h3>
Moles = Mass ÷ Molar mass
Molar mass of sodium nitrate = 84.9947 g/mol
Therefore,
Moles of NaNO₃ = 5.31 g ÷ 84.9947 g/mol
= 0.0625 moles
<h3>Step 2: Molarity of sodium nitrate </h3>
Remember;
Molarity = Moles ÷ Volume
Volume of NaNO₃ = 0.125 L
Therefore;
Molarity = 0.0625 moles ÷ 0.125 L
= 0.5 Moles/L or 0.5 M
Thus; the concentration of sodium nitrate is 0.5M
