Question

What is the molarity of 125 ml of solution containing 5.31 g sodium nitrate​

Answer 1

Answer:

0.5 moles/L or 0.5 M

Explanation:

• Molarity is the concentration of a solution in moles per liter.
• It is calculated by;

Molarity = Number of moles ÷ Volume

In this case;

Volume = 125 mL

Mass of sodium nitrate = 5.31 g

We are required to calculate the molarity of sodium nitrate

Step 1: Calculate the number of moles of sodium nitrate

Moles = Mass ÷ Molar mass

Molar mass of sodium nitrate = 84.9947 g/mol

Therefore,

Moles of NaNO₃ = 5.31 g ÷ 84.9947 g/mol

                            = 0.0625 moles

Step 2: Molarity of sodium nitrate

Remember;

Molarity = Moles ÷ Volume

Volume of NaNO₃ = 0.125 L

Therefore;

Molarity = 0.0625 moles ÷ 0.125 L

            = 0.5 Moles/L or 0.5 M

Thus; the concentration of sodium nitrate is 0.5M