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12345 [234]
2 years ago
5

Constance has an apple that weighs 85,000 milligrams and a peach that weighs 0.15 kilograms. which fruit has the greater mass? c

hoose the words and numbers to complete the statements. convert the masses of both fruits to the same unit. 85,000 milligrams is the same as choose... grams. 0.15 kilograms is the same as choose... grams. the choose... has the greater mass.
Chemistry
1 answer:
Rama09 [41]2 years ago
4 0

The fruit which has the greater mass is peach i.e. 150 grams.

<h3>What is mass?</h3>

Mass is a quantity which is used to define that what amount of substance will occupy any space or present in the given object.

We have given,

Weight of apples = 85,000 mg

Weight of peach = 0.15 kg

To compare the quantity first we have to convert both of these units in the same unit, and we know that:

In 1 kilogram = 1000 grams

And in 1 grams = 1000 milligrams

So, we convert both the units into grams as:

85,000 mg =  85,000 / 1000 = 85 grams

0.15 kg = 150 grams

So, the mass of peach is high.

Hence, peach has the greater mass.

To know more about mass, visit the below link:

brainly.com/question/15526412

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how much hydrogen will be released during the interaction of potassium weighing 8 grams with hydrochloric acid
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3 years ago
A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
3 years ago
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