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ratelena [41]
3 years ago
8

A sinusoidal wave is travelling on a string under tension T = 8.0(N), having a mass per unit length of 1 = 0.0128(kg/m). It’s d

isplacement function is D(x,t) = Acos(kx - t). It’s amplitude is 0.001m and its wavelength is 0.8m. It reaches the end of this string, and continues on to a string with 2 = 0.0512(kg/m) and the same tension as the first string. Give the values of A, k, and , for the original wave, as well as k and  the reflected wave and the transmitted wave.
Physics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

Explanation:

A sinusoidal wave is travelling on a string under tension T = 8.0(N), having a mass per unit length of 1 = 0.0128(kg/m). It’s displacement function is D(x,t) = Acos(kx - t). It’s amplitude is 0.001m and its wavelength is 0.8m. It reaches the end of this string, and continues on to a string with 2 = 0.0512(kg/m) and the same tension as the first string. Give the values of A, k, and , for the original wave, as well as k and  the reflected JJJJJJave and the transmitted wave.

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farmer joe drives a tractor for 4 hours. his tractor is pulling a heavy plow across a rocky field. over the course of 4 hours, i
marshall27 [118]

Over the course of the 4 hours for which farmer Joe's tractor is pulling the heavy plow, the plow is gaining energy by virtue of its displacement --termed the Kinetic energy.

According to the question, Farmer Joe drives the tractor for 4 hours.

However, the tractor is connected to a heavy plow and is used to pull the plow across a rocky field.

The question requires that we determine if the plow is gaining or losing energy.

  • In the plow's state of rest, prior to when it is connected to the tractor and pulled by the tractor; the plow possess a form of energy by virtue of its position termed the Potential energy.

However, the focus of the question is during the pulling action of the tractor on the plow.

  • As such, the plow now has a kinetic energy by virtue of its displacement..

Ultimately, the plow is gaining energy as it is being pulled by the tractor and now has Kinetic energy.

Read more:

brainly.com/question/15879747

3 0
2 years ago
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

C=\dfrac{8.85\times 10^{-12}\times 3.63^2\times 10^{-4}}{0.473\times 10^{-3}}

C=2.46 x 10⁻¹¹ F

U=\dfrac{1}{2}CV^2

V=Voltage difference

V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

7 0
4 years ago
While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.1 km away from the ac
kolezko [41]

Answer:

The time that will pass between the feeling and hearing the explosion is 2,86 secs

Explanation:

First, let's calculate the time that the wave takes to travel until the actors feel the explosion:

1,1 km*\frac{1.000 mts}{1 km} *\frac{sec}{3.000 mts} = 0,37 secs

Now, the time that pass while the actors hear the sound is:

<em>(Remember that the sound speed in the air is 340 m/s on average)</em>

1,1 km * \frac{1.000 mts}{1 km} * \frac{sec}{340 mts} = 3,23 secs

So, the time between the feeling and hearing is 3,23 - 0,37 = 2,86 secs

4 0
4 years ago
What is the magnitude of the dipole moment formed by separating a proton and an electron by 80 pm ?
asambeis [7]

dipole moment is defined as product of charge and distance between between.

P = qd

q = 1.6 \times 10^{-19} C

d = 80 pm = 80 \times 10^{-12} m

P = (1.6 \times 10^{-19})(80 \times 10^{-12})

P = 1.28 \times 10^{-29} Cm

so above is the dipole moment of the given charges

5 0
3 years ago
A 150-newton force, applied to a wooden crate at an angle of 30° above the horizontal, causesthe crate to travel at constant vel
omeli [17]

Answer:

Explanation:

A component of 150 N in vertical direction will reduce the magnitude of reaction force.

reaction force exerted by the floor

= mg - 150 sin 30

where m is mass of the crate .

the magnitude of the horizontal component of the 150-newton force

150 cos30

= 130 N

This force tries to pull the crate in forward direction with acceleration but it has no acceleration . It is so because frictional force of equal magnitude acts on it in opposite direction which makes the net force acting on it equal to zero.

Hence frictional force is equal to 150 cos 30.

= 130 N .

3 0
4 years ago
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