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serg [7]
3 years ago
12

Why are circles so important in creating equilateral triangles

Mathematics
1 answer:
Daniel [21]3 years ago
6 0
Maybe because the diameter of the circle should equal each side length of te equilateral triangle 
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A small lizard is five sixth inch long. A larger lizard is 6 and four fifths times larger. How long is the larger lizard?
Ulleksa [173]

Answer:

170/30 inches Larger Lizard

Step-by-step explanation:

Small lizard   5/6 inches long

Larger lizard 6 4/5 times (x) larger than the small lizard 5/6 inches long

Step 1. Try to make everything the same before doing anything else. You can do this by getting rid of the whole number in 6 4/5 :

Use the denominator of this equation 6(4/5 ), which is 5, with the whole number (6) and then the add the numerator (4) to it. Example,   5x6= 30,  30+4=34 ,   you now have   34/5  . Now it is the same as 5/6

Since the size of the larger lizard is 34/5 longer than the size of the small lizard, all you have to do is multiply the fractions together to get your answer;

                     (5/6) x (34/5)= Numerator 5x34=170 , Denominator 5x6=30    

Your answer is: Numerator/Denominator   ===>    170/30  

The larger lizard is 170/30 inches long or, 17/3 inches long.

5 0
3 years ago
What is the formula to calculate the perimeter of the circle​
Lapatulllka [165]

Answer:

2πr

Step-by-step explanation:

when we use this formula it will come ans

please i think it is right

please follow me ok

4 0
3 years ago
Read 2 more answers
What is y= (5x+7) (-2x+3) in standard form
nikitadnepr [17]

Answer:

y = 10x^2 + x +21

Step-by-step explanation:

3 0
3 years ago
Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly s
barxatty [35]

Answer:

0 tests

Yes, this procedure is better on the average than testing everyone, it makes it less cumbersome.

Step-by-step explanation:

Given the information:

Let P be the probability that a randomly selected individual has the disease = 0.1. N individuals are randomly selected, thereafter, blood samples of each person would be tested after combining all specimens. Should in case one person has the disease then it yields a positive result and test should be set for each person.

Let Y be number tests

For n = 3 there are two possibilities. If no one has the disease then the value is 1 otherwise the value is 4, here P = 0.1

Therefore, for Y = 1

P(Y-1) = P(no one has disease)

= 0.9³

= 0.729

If Y = 4

P(Y-4) = 1-P(y = 1)

= 1 - 0.729 = 0.271

The expected number of tests using this formular gives

E(Y) = 1×0.729 + 4×0.271

E(Y) = 0

4 0
4 years ago
Which expression uses the associative property to make it easier to evaluate 6(3/2x1/5) ?
agasfer [191]
I think the answer is B but I’m not sure, sorry if i got it wrong,

have a good day and have a good Christmas
7 0
3 years ago
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