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3 years ago

How do you do this question?

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Answer:

-1

Step-by-step explanation:

dy/dt = y² − 1 = (y + 1) (y − 1)

At t = 0, y = 0, and dy/dt = -1. Therefore, y is initially decreasing.

As y decreases, dy/dt increases. When y = -1, dy/dt = 0 and changes signs from negative to positive.

As y increases above -1, dy/dt again becomes negative. So y continues to approach -1 as t approaches infinity.

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Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

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2 years ago

amy places adopt on a coordinate plane at (-3,-6) she wants to place another dot across the y-axis and it must be 8 points away.

Vaselesa [24]

(5,-6) because across the y acis meanes the same y Val just a different x Val. and so you could count 8 away from -3 going right. and you'll get my answer

6 0

3 years ago

Read 2 more answers

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

Read 2 more answers

Find the volume of each figure. Round your answers to the nearest hundredth, if necessary

SCORPION-xisa [38]

Answer:

666.67π .ft^3

here's your solution

=> radius of cone = 10 ft

=> height of cone = 20 ft

=> volume of cone = πr^2h/3

=> putting the value of radius and height

=> volume = 10^2*20/3π

=> volume = 666.67π .ft^3

hope it helps

5 0

2 years ago

What is 11% of 650 please?

Debora [2.8K]

578.5 is your answer.

take 650 x .11 and you get 71.5.
take 650 - 71.5 = 578.5

6 0

3 years ago