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Lerok [7]
3 years ago
11

Someone please help me answer this question

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0
The answer is 1.5 mg
Rasek [7]3 years ago
5 0

Answer:

reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

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Caroline took a math test and got 19 out of 25 questions correct. What percent of the questions did she answer correctly?
algol [13]

Answer:

76%

Step-by-step explanation:

do the amount of correct answers divided by the total of questions asked.

5 0
3 years ago
I’ll give brainliest
kupik [55]

Answer:

Area= (12^2)pi

Step-by-step explanation:

Area= 150/360 (pi12^2)

= 188.5 total area

5 0
3 years ago
Two chemical companies can supply a raw material. The concentration of a particular element in this material is important. The m
svp [43]

Answer:

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

Step-by-step explanation:

As we suspect the variability of concentration F - test is applied.

n1=10    s1=4.7

n2=16      s2=5.8

And α = 0.05.

The null and alternate hypothesis are

H0: σ₁²=σ₂²       Ha:  σ₁²≠σ₂²

The null hypothesis is  the variability in concentration does not  differ for the two companies.

against the claim

the variability in concentration may differ for the two companies

The critical region F∝(υ1,υ2) = F(0.025)9,15= 3.12

and 1/F∝(υ1,υ2) = 1/3.77= 0.26533

where υ1= n1-1= 10-1= 9 and υ2= n2-1= 16-1= 15

Test Statistic

F = s₁²/s₂²

F= 4.7²/5.8²=0.6566

Conclusion :

As the calculated F lies in the acceptance region therefore we conclude that there is not sufficient evidence to support the claim that the variability in concentration may differ for the two companies. Hence Ha is rejected and H0 is accepted.

3 0
3 years ago
Victor spend a total of 33 picture and text messages which cost 8.30.if text message rate is .18 per message and the picture mes
malfutka [58]
Ok so

t=number of text messsages
p=number of picture messages

total number is 33
t+p=33

if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830



we now have 2 equations
t+p=33
18t+45p=830

multiply first equation by -18 and add to second equation

18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236

27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
7 0
3 years ago
May someone help me with 2-9? Please?
mylen [45]

2. Each side of a pentagon is the same size.

4cm x 5 = 20cm or 4cm+4cm+4cm+4cm+4cm = 20cm

3. Each side of a square is the same size.

13yd x 4 = 52yd or 13yd+13yd+13yd+13yd = 52yd

4. Add all sides together.

12m+12m+30m+30m = 84m

5. Again add all sides together.

16yd+16yd+4yd+4yd = 40yd

6. Each side of a square is the same size.

7in x 4 = 28in. or 7in+7in+7in+7in = 28in

7. Add all sides together.

2cm+2cm+3cm+3cm = 10cm

8. Each side of a rhombus is the same size. A rhombus has 4 sides.

23in x 4 = 92in or 23in+23in+23in+23in = 92in

9. A regular octagon has 8 sides and each side is the same size.

9cm x 8 = 72cm

7 0
4 years ago
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