Answer:
A.
Step-by-step explanation:
There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
Point-slope form is written as : y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point.
The slope (m) is found by the change in Y over the change in X
Slope = (y2 - y1) / (x2 - x1)
You can use either given point for x1 and y1 so you would calculate the slope and replace m with the slope, then replace x1 and y1 in the equation with their value.
Answer:
-23
Step-by-step explanation:
Let first negative integer = x
The second = x +5
Their product = 126, hence,
x * (x +5) = 126
x^2 + 5x = 126
x^2 + 5x - 126 = 0
Two numbers whose product gives - 126 and sun gives 5
x(x + 14) - 9(x+14) =0
(x - 9) = 0 or (x + 14) = 0
x = 9 or x = - 14
Since x is said to be a negative integer,, the our x = - 14
First integer = - 14
Second integer = (x + 5) = (-14 + 5) = - 9
Sum of both integers :
-14 + - 9 = - 23
Answer:
4a. 41, 4b. 26.2, 4c. 42.8, 4d. 27.05 26.2, 27.05, 41, 42.8
Step-by-step explanation:
