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qwelly [4]
3 years ago
15

A flagpole casts a shadow 8.5 meters long. if an algebra student 1.6 meters tall casts a shadow 2.0 meters long at the same time

and location, how tall is the flagpole
Mathematics
2 answers:
MrMuchimi3 years ago
5 0
<span>The flagpole stands vertically on the ground. If a line is drawn from the top of the flagpole to the shadow, it forms a right-angled triangle. Similarly, if a line is drawn from the top of the student's head to the tip of this shadow a right-angled triangle is formed. Since it is given that the measures of both the shadows are taken at the same time and location, the angle of depression in both the cases is equal. Therefore, by AA similarity, height of the flagpole/ height of the student =length of shadow of the flagpole/length of shadow of the student flagpole height/1.6m = 8.5 m/2.0m flagpole height = (8.5 m x 1.6m )/2.0 m =6.8m</span>
GarryVolchara [31]3 years ago
5 0
Similar triangles, the corresponding sides have the same ratio
 let f = height of the flag pole
 f/1.6=8.5/2
 Cross multiply
 2f = 1.6 * 8.5
 2f = 1.6 * 8.5
 f=13.6/2
 f=6.8
 the flagpole is 6.8 m tall
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The 3 × 3 matrix P satisfies the matrix equation P^2 = P.
riadik2000 [5.3K]

Answer:  The answers are given below.

Step-by-step explanation:  Given that a  3 × 3 matrix P satisfies the matrix equation P² = P.

We are to

(a) find the possibilities for the determinant of P.

(b) explain the reason behind there are no other possibilities.

(c) give an example of P, for each possible determinant.

(a) According to the given information, we have

P^2=P\\\\\Rightarrow P^2-P=0\\\\\Rightarrow P(P-I)=0\\\\\Rightarrow P=0,~~~P=I.

So, P can be either a zero matrix of order 3 or an identity matrix of order 3.

If P = 0, then det(P) = 0     and     if P = I, then det(P) = 1.

Therefore the possible determinants of P are 0 and 1.

(b) There can be any other determinant other than 0 and 1, because if so, then the given equation P² = P will not be satisfied.

(c) If |P| = 0, then the matrix P can be can be of the form as follows:

P=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right] .

If |P| = 1, the the matrix P can be of the form as follows :

P=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] .

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4 0
3 years ago
Between what two consecutive whole numbers does 42 lie.
lana66690 [7]
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4 0
3 years ago
Evaluate the function f\left(x\right)=5x+2\mid11-5x\mid-4f(x)=5x+2∣11−5x∣−4 for x = -5.
Anestetic [448]

Answer:

f\left(5\right) = 43

Step-by-step explanation:

Given

f\left(x\right)=5x+2\mid11-5x\mid-4

Required

Solve for x = -5

This implies that we substitute -5 for x in f\left(x\right)=5x+2\mid11-5x\mid-4

f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4

Open all brackets

f\left(5\right) = -25+2\mid11+25\mid-4

f\left(5\right) = -25+2\mid36\mid-4

Absolute value of 36 is 36; Wo, we have:

f\left(5\right) = -25+2*36-4

f\left(5\right) = -25+72-4

f\left(5\right) = 43

7 0
3 years ago
Whats 21 3/4 ÷ 2 1/2 = ???
galben [10]
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8 0
3 years ago
Read 2 more answers
Subtract: 4x/x^2-25 - 2/x^2+2x-15
Alex777 [14]

Answer: \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

Step-by-step explanation:

Given

Subtract the expression

\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

4 0
3 years ago
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