Answer: Provided.
Step-by-step explanation: We are given two lines 'h' and 'k' which are parallel to each other. Also, there is another line 'j' that is perpendicular to line 'h'.
We are to prove that line 'j' is perpendicular to line 'k'.
Let, m, n and p be the slopes of lines 'h', 'k' and 'j' respectively.
Now, since line 'h' and 'k' are parallel, so their slopes will be equal. i.e., m = n.
Also, lines 'h' and 'j' are perpendicular, so the product of their slopes is -1. i.e.,
m×p = -1.
Hence, we can write from the above two relations
n×p = -1.
Thus, the line 'j' is perpendicular to line 'k'.
Proved.
I believe the answer would be A. 2x-y=6 :)
Step-by-step explanation:
-3x-9
divide the equation by -1 so that the -1's are taken from -3x and -9. so the -1 goes on the outside of 3x+9
-1(3x+9)
then divide the equation by 3 since 3x and 9 is divisible by 3.
(-1)(3)(3/3x+9/3)
-3(x+3)
Now we can expand again to check the problem
-3 times x=-3x
-3 times 3=-9
and add
-3x-9
Hope that helps :)