Answer:



Explanation:
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In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:



Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:
Ka1 > Ka2 > Ka3
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The molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.
<h3>How to calculate molar heat of fusion?</h3>
The heat of fusion of a substance can be calculated by using the following formula:
Q = m∆H
Where:
- Q = quantity of heat
- m = mass
- ∆H = change in temperature of fusion
However, the quantity of heat has been given as 9840calories. The molar heat of fusion of iron can be calculated by dividing the heat of fusion by the number of moles of iron.
Moles of iron = mass ÷ molar mass
moles = 200g ÷ 55.8g/mol
moles = 3.58moles
molar heat of fusion = 9840 cal ÷ 3.58mol
molar heat of fusion = 2748.6 cal/mol
Therefore, the molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.
Learn more about molar heat of fusion at: brainly.com/question/8263730