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dimaraw [331]
2 years ago
14

An element gave off a wavelength of 4.8x10^-7 m. What is the frequency of the element?(needs unit, and 3 sig-figs) *

Chemistry
1 answer:
Archy [21]2 years ago
8 0

Answer : The frequency of element is, 6.25\times 10^{14}s^{-1}

Explanation : Given,

Wavelength of element = 4.8\times 10^{-7}m

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency

\lambda = wavelength

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{4.8\times 10^{-7}m}

\nu=6.25\times 10^{14}s^{-1}

Therefore, the frequency of element is, 6.25\times 10^{14}s^{-1}

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From standard reduction potentials, calculate the equilibrium constant at 25 ∘c for the reaction 2mno−4(aq)+10cl−(aq)+16h+(aq)→2
garik1379 [7]

Answer:

\boxed{\text{57.9}}

Explanation:

Step 1. Determine the cell potential

                                                                                 <u>     </u><u>E°/V</u><u>      </u>

2MnO₄⁻ + 16H⁺ + 10e⁻ → 2Mn²⁺+ 8H₂O                      1.507

<u>10Cl⁻ ⟶ 5Cl₂ + 10e⁻                                             </u>     <u>-1.358 27 </u>

2MnO₄⁻ + 10Cl⁻ + 16H⁺⟶ 2Mn²⁺ + 5Cl₂ + 8H₂O      0.149

Step 2. Calculate K

The formula relating K and E is

E = \dfrac{RT}{nF} \ln K

E = 0.149 V

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C = 298.15 K

n = 10

F = 96 485 C/mol

0.149 = \dfrac{8.314 \times 298.15}{10\times 96 485} \ln K\\\\0.149 = 0.002 570 \ln K\\\\\ln K = \dfrac{0.149}{0.002570} = \textbf{57.9}

The value of the equilibrium constant is \boxed{\textbf{57.9}}

6 0
2 years ago
Some people think that wind power should be used for all the electricity in the United States. Which argument could be used to d
Marianna [84]
There might not be ample enough wind to power all the electricity in the United States and in some places there might not be wind at all so people wouldn't be able to have electricity.
4 0
2 years ago
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Plz help guys ASAP! <br> Thanks in advance
MariettaO [177]

Answer:

3.6 moles

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂ to produce 2 moles NH₃.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N₂ reacted with 3 moles of H₂.

Therefore, 3.2 moles of N₂ will react with = 3.2 × 3 = 9.6 moles of H₂.

From the calculation made above, we can see that it will take a higher amount (i.e 9.6 moles) of H₂ than what was given (i.e 5.4 moles) to react completely with 3.2 moles of N₂.

Therefore, H₂ is the limiting reactant and N₂ is the excess reactant.

Finally, we the greatest quantity of ammonia, NH₃ produced from the reaction.

In this case, the limiting reactant will be use because all of it is consumed in the reaction.

The limiting reactant is H₂ and greatest quantity of ammonia, NH₃ produced can be obtained as follow:

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, 5.4 of H₂ will react to produce = (5.4 × 2)/3 = 3.6 moles of NH₃

Thus, the greatest quantity of ammonia, NH₃ produced from the reaction is 3.6 moles

4 0
3 years ago
Calculate the osmotic pressure of a solution containing 24.6g of glycerin in 250ml of solution at 298K
gavmur [86]
The formula to calculate osmotic pressure is 
Osmotic Pressure = M R T
M = Molarity
R = Ideal Gas Constant
T = Temperature in Kelvin

So, 
24.6/.2254kg=109.139g /kg  >>>>> Molarity
109.139 x mols/92 g = 1.186 mols kg^-1
1.186 x 0.08134 x 298 K = 28.755 atm
<span>1.06852 x 0.08134 x 298K= 26.5 atm

The answer is 26.5</span>
6 0
3 years ago
What are 4 general properties of matter?
Law Incorporation [45]
1. Solid
2. Liquid
3. Gas
4. Plasma
3 0
2 years ago
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