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Westkost [7]
3 years ago
5

Which of these are examples of physical changes? Check all that apply. burning wood freezing water cutting paper iron rusting mi

xing water and acetone
Chemistry
2 answers:
rodikova [14]3 years ago
5 0
Cutting paper
freezing water
mixing water
acetone
Colt1911 [192]3 years ago
4 0

<u>Answer:</u>

freezing water

cutting paper

mixing water and acetone




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What is the temperature of 0.47 mol of gas at a pressure of 1.5 atm and a volume of 10.5 l ?
Whitepunk [10]
The temp is 0.002448 of the equation
5 0
3 years ago
Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
Read 2 more answers
After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905
julia-pushkina [17]

The sign's glass absorbed 25466.7 J

<h3>Further explanation</h3>

Given

The temperature of glass :  23.5 °C to 65.5 °C

mass = 905 g

the specific heat capacity = 0.67 J/g °C

Required

Heat absorbed

Solution

Heat absorbed by sign's glass can be formulated :

\tt Q=m.c.\Delta T

ΔT=65.5 - 23.5 = 42

\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}

5 0
2 years ago
Read 2 more answers
Bacon head chicken noob
dangina [55]

Answer:

alright that sounds like a recipe i gota try

5 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
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