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Vinil7 [7]
4 years ago
11

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

ure Y-:X:-Y could be abbreviated as XY2Z2.
Classify these structures according to their shape.
XY2Z,XY2Z2,XY2Z3,XY3Z,XY3Z2,XY4Z,XY4Z2,XY5Z The categories are linear, bent(~120), bent(~109), trigonal pyramidal, t-shaped, see-saw, square planar, square pyramidal
Chemistry
2 answers:
Nadya [2.5K]4 years ago
7 0
 <span>XY4Z2-->Square planar (Electron domain geometry: Octahedral) sp3d2 
XY4Z-->Seesaw (Electron domain geometry: Trigonal bipyramidal) sp3d 
XY5Z-->Square pyramidal (Electron domain geometry: Octahedral) sp3d2 
XY2Z3-->Linear (Electron domain geometry: Trigonal bipyramidal) sp3d 
XY2Z-->Bent (Electron domain geometry: Trigonal planar) sp2 
XY3Z-->Trigonal pyramidal (Electron domain geometry: Tetrahedral) sp3 
XY2Z2-->Linear (Electron domain geometry: Tetrahedral) sp3 
XY3Z2-->T shaped (Electron domain geometry: Trigonal bipryamidal) sp3d 
XY2-->Linear (Electron domain geometry: Linear) sp 
XY3 Trigonal planar (Electron geometry: Trigonal planar) sp2 
XY4-->Tetrahedral (Electron domain geometry: tetrahedral) sp3 
XY5-->Trigonal bipyramidal (Electron domain geometry: Trigonal bipyramidal) sp3d 
XY6-->Octahedral (Electron domain geometry: Octahedral) sp3d2</span>
Brut [27]4 years ago
5 0

Answer:

1) Bent(120)

2) Bent (109)

3) Linear

4)Trigonal Pyramidal

5)t-shaped

6)see-saw

7)Square planar

8)Square pyramidal

Explanation:

1) XY₂Z:

Central atom = X

# Bonds around X = 2 X-Y bonds

# Lone pairs = 1

Shape = Bent (~120)

2) XY₂Z₂:

Central atom = X

# Bonds around X = 2 X-Y bonds

# Lone pairs = 2

Shape = Bent (~109)

3) XY₂Z₃:

Central atom = X

# Bonds around X = 2 X-Y bonds

# Lone pairs =3

Shape = Linear

4) XY₃Z:

Central atom = X

# Bonds around X = 3 X-Y bonds

# Lone pairs = 1

Shape = Trigonal Pyramidal

5) XY₃Z₂:

Central atom = X

# Bonds around X = 3 X-Y bonds

# Lone pairs = 2

Shape = t-shaped

6) XY₄Z:

Central atom = X

# Bonds around X = 2 X-Y bonds

# Lone pairs = 1

Shape = see-saw

7) XY₄Z₂:

Central atom = X

# Bonds around X = 4 X-Y bonds

# Lone pairs = 2

Shape = Square planar

8) XY₅Z:

Central atom = X

# Bonds around X = 5 X-Y bonds

# Lone pairs = 1

Shape = Square pyramidal

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4.0 L sample of methane gas is collected at 30.0c,<br> what is the volume of the sample at -8c?
Vedmedyk [2.9K]
This particular law is a gas law, called Charle's Law. The formula is:

V1    V2
---- = ----
T1     T2

So we know our original volume is 4.0L, so we would plug that into our V1. We know T1 is the 30 degrees, since it relates to our original volume. However, we need to convert it to kelvin. We do this simply by adding 273 degrees to the 30 degrees, since 273 is the constant for kelvin.

We do not know our second volume, however we know out T2. It is -8 degrees, and don't forget to convert it to Kelvin. 

So, when we plug all of these numbers into the equation, we are left with V2 to find. To do this we cross multiply (V1 x T2) and then divide by T1. That leaves us with the number for V2. Don't forget to round to the least # of sig figs! And you can divide V1 by T1, and then divide V2 by T2, to ensure your answers are the same, since they are directly porportional and need to be equal to each other. 

Hope I could help!
8 0
4 years ago
An 8.89 g sample of an aqueous solution of nitric acid contains an unknown amount of the acid. If 27.1 mL of 0.581 M potassium h
worty [1.4K]

Answer:

The percent by mass of nitric acid in the mixture is 11.1 %

Explanation:

Step 1: Data given

Mass of HNO3 = 8.89 grams

Volume of KOH = 27.1 mL = 0. 0271 L

Molarity of KOH = 0.581 M

Step 2: The balanced equation

HNO 3  +  KOH  →  KNO 3  +  H 2 O

Step 3: Calculate the moles of KOH

Moles of KOH = molarity KOH * volume

Moles KOH = 0.581 M * 0.0271 L

Moles KOH = 0.0157 moles

Step 4: Calculate moles of HNO3

For 1 mol of KOH we need 1 mol of HNO3

For 0.0157 moles of KOH we need 0.0157 moles of HNO3

Step 5: Calculate mass of HNO3

Mass KOH = moles KOH * molar mass KOH

Mass KOH = 0.0157 moles * 63.01 g/mol

Mass KOH = 0.989 grams

Step 6: Calculate mass % HNO3 in sample

mass % = (0.989 grams / 8.89 grams)*100%

mass % = 11.1 %

The percent by mass of nitric acid in the mixture is 11.1 %

3 0
4 years ago
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Damm [24]

Answer:

i dont know but it is probily 4 and 6

5 0
2 years ago
Richard sketched models of two different neutral isotopes of oxygen. If the
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Answer:c

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5 0
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Answer:

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Explanation:

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