Sound waves in air are a series of <span>periodic disturbances, </span><span>periodic condensations and rarefactions,</span><span> and high- and low-pressure regions. It is all of the above. The answer is letter D.</span>
No. I do not agree with Stefan. Quite the contrary. I disagree
with his description of "<span>angle of incidence" as the angle between
the surface of the mirror and the incoming ray.
The correct description of "angle of incidence" is </span><span>the angle between
the NORMAL TO the surface of the mirror and the incoming ray.
Thus, the true angle of incidence is the complement of the angle that
Stefan calculates or measures.</span>
Assume <em>R</em> is measured in meters (m) and <em>M</em> in kilograms (kg). Then
<em>R</em> ² / (<em>GM</em>) = [m]² / ([N•m²/kg²] [kg]) = m•kg / N = m•kg / (kg•m/s²) = s²
so <em>t</em> ² is indeed proportional to <em>R</em> ²/(<em>GM</em>).
Answer:
10.337m/s2
Explanation:
F=ma
a=F/m
a = 92 / 8.9 = 10.337m/s2
Explanation:
It is given that,
Radius of loop, r = 78 mm = 0.078 m
Current, I = 114 A
(a) Magnetic field strength of the circular loop is given by :
B = 0.000918 T
or
(b) Energy density at the center of the loop is given by :
Hence, this is the required solution.
