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ipn [44]
2 years ago
8

The primary gas in a volcano is: carbon dioxide, sulfur dioxide, water vapor, nitrogen.

Physics
2 answers:
vaieri [72.5K]2 years ago
7 0

Answer:

The primary components in volcanic gas are water vapor, carbon dioxide and sulfur (either sulfur dioxide or hydrogen sulfide). But you can also find nitrogen, argon, helium, neon, methane, carbon dioxide and hydrogen. Approximately 60% of total emissions released by volcanoes is water vapor, and carbon dioxide accounts for 10 to 40% of emissions.

Explanation:

Mice21 [21]2 years ago
6 0

Answer:

Water vapor

Explanation:

The magma consists of dissolved gases when these gases produce the force the volcanic eruption takes place. The volcanic gases come out and their volume is increased tremendously. The gases present in the volcano are listed below:

The volcanic gases consist of water vapors, carbon dioxide, and sulfur.

These three are the primary gases but the water is present in a higher amount.

The percentage of water is 60%.

The carbon dioxide present in 10-40%.

Other gases present in volcanos are nitrogen, argon, helium, neon methane, and hydrogen.

Hope this helps, Let me know if I am wrong ( I am pretty sure that am not) but let me know anyway..., OH! and Good LUCK! :D ;P

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A rescue airplane is diving at an angle of 37º below the horizontal with a speed of 250 m/s. It releases a survival package when
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Answer:

<em>The correct option is 1.  720 m</em>

Explanation:

<u>Projectile Motion</u>

When an object is launched in free air (no friction) with an initial speed vo at an angle \theta, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.

\displaystyle V_o=250\ m/s

\displaystyle \theta =-37^o

The initial velocity has these components in the x and y coordinates respectively:

\displaystyle V_{ox}=250\ cos(-37^o)=199.7\ m/s

\displaystyle V_{oy}=250\ sin(-37^o)=-150.5\ m/s

And we know the plane has an altitude of 600 m, so the package will reach ground level when:

\displaystyle y=-600\ m

The vertical distance traveled is given by:

\displaystyle y=V_{oy}\ t-\frac{g\ t^2}{2}=-600

We'll set up an equation to find the time when the package lands

\displaystyle -150.5t-4.9\ t^2=-600

\displaystyle -4.9\ t^2-150.5\ t+600=0

Solving for t, we find only one positive solution:

\displaystyle t=3.6\ sec

The horizontal distance is:

\displaystyle x=V_{ox}.t=199.7\times3.6=720\ m

The correct option is 1.  720 m

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