Answer:
c
Explanation:
propagation means starting point, and waves travel from the starting point forward until something changes the direction of the waves. good luck!
Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s
Explanation:
(a) The period of a wave is the time required for one complete cycle. In this case, we have the time of five cycles. So:
![T=\frac{t}{n}\\\\T=\frac{50.2s}{5}\\T=10.04s](https://tex.z-dn.net/?f=T%3D%5Cfrac%7Bt%7D%7Bn%7D%5C%5C%5C%5CT%3D%5Cfrac%7B50.2s%7D%7B5%7D%5C%5CT%3D10.04s)
(b) The frequency of a wave is inversely proportional to its period:
![f=\frac{1}{T}\\f=\frac{1}{10.04s}\\f=0.01Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7BT%7D%5C%5Cf%3D%5Cfrac%7B1%7D%7B10.04s%7D%5C%5Cf%3D0.01Hz)
(c) The wavelength is the distance between two successive crests, so:
![\lambda=30.2m](https://tex.z-dn.net/?f=%5Clambda%3D30.2m)
(d) The speed of a wave is defined as:
![v=f\lambda\\v=(0.1Hz)(30.2m)\\v=3.02\frac{m}{s}](https://tex.z-dn.net/?f=v%3Df%5Clambda%5C%5Cv%3D%280.1Hz%29%2830.2m%29%5C%5Cv%3D3.02%5Cfrac%7Bm%7D%7Bs%7D)
Final velocity = Vf=0 <span>
Initial velocity = Vi = 9.5m/s
Acceleration = a = -4.6m/s</span>²<span>
Time = t =? </span>
Now use the formula;<span>
Vf=Vi+at
<span>0=9.5 - 4.6m/s</span></span>²t
<span>
-9.5 = -4.6m/s</span>²(t)
9.5/4.6 = t<span>
<span>T= 2.01s</span></span>
<span>1. capable of being dissolved in a liquid= Soluble
</span><span>
2. not capable of being dissolved in a liquid= Insoluble
</span><span>3. to break up in unit parts to form a solution= Dissolve
</span>
<span>4. the substance that is dissolved in the solution= Solute
</span>
<span>5. the substance that does the dissolving= Solvent
please be more clear in the way you word you questions from now on. I had a hard time understanding what you meant. I hope this helps.
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