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Leno4ka [110]
3 years ago
15

A production machine that consists of three components connected in series. The first component follows Weibull probability dist

ribution with shape parameter of 1.3 and scale parameter (characteristic life) of 24,000 hr. The second follows Weibull probability distribution with shape parameter of 1.9 and scale parameter (characteristic life) of 18,000 hr. The third component follows exponential distribution with MTTF= 48,000 hr. Find the reliability of the system at t = 6000
Physics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

The correct solution is "0.66104".

Explanation:

Given:

Component 1,

\beta=1.3

\gamma=24,000 \ hr

Component 2,

\beta = 1.9

\gamma=18,000 \ hr

Component 3,

MTTF=48,000 \ hr

Now,

At t = 6000 hr, the system reliability will be:

⇒ Rs(t=6000)=\frac{3}{\pi} R_1\times R_2\times R_3

                         =[e^{-(\frac{6000}{24000} )^{1.3}}]\times [e^{-(\frac{6000}{18000} )^{1.9}}]\times [e^{-(\frac{6000}{48000} )}]

                         =0.66104

Thus the above is the correct solution.

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Eighteen percent

Explanation:

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8 0
3 years ago
An object is spun around in circular motion such that its frequency is 12 Hz.
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Explanation:

Given parameters:

Frequency  = 12Hz

Unknown:

a. Period of its rotation

b. Time required to complete 86 rotations

Solution:

Frequency is the number of times of rotation per unit of time.

  Frequency  = \frac{n}{t}  

Period is the opposite of frequency;

          Period = \frac{1}{12}   = 0.083s

b. Time for 86 rotations;

          Since frequency  = \frac{n}{t}  

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t is the time

             t  = \frac{n}{Frequency}  = \frac{86}{12}   = 7.2s

4 0
3 years ago
Doug, who runs track for his high school, was challenged to a race by his younger brother, matt. Matt started running first, and
eduard

The speed of Matt is 10 mph.

Doug runs 2 miles an hour faster than Matt, so let Matt’s speed equal x miles per hour. Then Doug’s speed equals x + 2 miles per hour. Each lap is one-quarter of a mile, so Doug runs 1.5 miles in the time it takes Matt to run 1.25 miles.

Rate of Matt is x

Rate of Dough is (x + 2)

Time taken by Matt is 1.25/x

Time taken by Dough is 1.25/(x + 2)

Distance covered by Matt is 1.25

Distance covered by Dough is 1.5

Dough and  Matt  took the same amount of time from the time Doug started, so make an equation by setting the two times in the chart equal to each other, and then solve for x:

            \frac{1.5}{(x + 2)} = \frac{1.25}{x}

              1.5x = 1.25(x + 2)

              1.5x = 1.25x + 2.5

           0.25x = 2.5

                   x = 10

So Matt ran at 10 miles per hour.

To know more about time, speed and distance, visit: brainly.com/question/26046491

#SPJ4

7 0
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