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Leno4ka [110]
3 years ago
15

A production machine that consists of three components connected in series. The first component follows Weibull probability dist

ribution with shape parameter of 1.3 and scale parameter (characteristic life) of 24,000 hr. The second follows Weibull probability distribution with shape parameter of 1.9 and scale parameter (characteristic life) of 18,000 hr. The third component follows exponential distribution with MTTF= 48,000 hr. Find the reliability of the system at t = 6000
Physics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

The correct solution is "0.66104".

Explanation:

Given:

Component 1,

\beta=1.3

\gamma=24,000 \ hr

Component 2,

\beta = 1.9

\gamma=18,000 \ hr

Component 3,

MTTF=48,000 \ hr

Now,

At t = 6000 hr, the system reliability will be:

⇒ Rs(t=6000)=\frac{3}{\pi} R_1\times R_2\times R_3

                         =[e^{-(\frac{6000}{24000} )^{1.3}}]\times [e^{-(\frac{6000}{18000} )^{1.9}}]\times [e^{-(\frac{6000}{48000} )}]

                         =0.66104

Thus the above is the correct solution.

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Mkey [24]

Answer:

   F = 20.4 i ^

Explanation:

This exercise can be solved using the ratio of momentum and amount of movement.

     I = F t = Dp

Since force and amount of movement are vector quantities, each axis must be worked separately.

X axis

Let's look for speed

      cos 45 = vₓ / v

      vₓ = v cos 45

      vₓ = 8 cos 45

      vₓ = 5,657 m / s

We write the moment

Before the crash                          p₀ = m vₓ

After the shock                            p_{f} = -m vₓ

The variation of the moment      Δp = mvₓ - (-mvₓ) = 2 m vₓ

The impulse on the x axis           Fₓ t = Δp

       

        Fₓ = 2 m vₓ / t

        Fx = 2 0.450 5.657 / 0.250

        Fx = 20.4 N

We perform the same calculation on the y axis

       sin  45 = vy / v

       vy = v sin 45

       vy = 8 sin 45

       vy = 5,657 m / s

We calculate the initial momentum   po = m v_{y}

Final moment                                      p_{f} = m v_{y}

Variations moment                             Δp = mv_{y} - mv_{y} = 0

Force in the Y-axis                             F_{y} = 0

Therefore the total force is

       F = fx i ^ + Fyj ^

       F = Fx i ^

       F = 20.4 i ^

3 0
4 years ago
Imagine that you have two marbles on a table. You roll one marbles towards another. When the marble collide, the marble at rest
Alika [10]

Because that's called friction. When to things collide it causes friction which makes them stop rolling>

8 0
3 years ago
A skateboarder travels on a horizontal surface with an initial velocity of 4.0 m/s toward the south and a constant acceleration
Alenkinab [10]

Answer:

a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s

Explanation:

a)

  • As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
  • This means that we can use the kinematic equations for displacements along both axes.
  • In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

        x =\frac{1}{2}*a*t^{2} (1)

  • In the y-direction, as no acceleration is acting on the skateboarder, we can write  the following displacement equation:

        y = v_{0y} * t  (2)

  • For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

       x =\frac{1}{2}*a*t^{2} =\frac{1}{2} * 1.8 m/s2*(0.6s)^{2}\\ x = 0.32 m

b)

  • From (2) we can get the position on the y-axis (displacement from the origin) as follows:

        y = v_{0y} * t  =  -4 m/s * 0.6 s = -2.4 m

c)

  • In the x- direction, we can find the component of the velocity along this direction, as follows:

        v_{fx} = a*t

  • Replacing by the values, we have:

        v_{fx} = a*t = 1.8 m/s2 * 0.6 s = 1.08 m/s

d)

  • As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we  have:

        vfy = voy = -4 m/s

8 0
4 years ago
Water drips from the nozzle of a shower onto the floor 189 cm below. The drops fall at regular (equal) intervals of time, the fi
laiz [17]

Answer:

0.83999 m

0.20999 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s = 189 cm

s=ut+\frac{1}{2}at^2\\\Rightarrow 1.89=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.89\times 2}{9.81}}\\\Rightarrow t=0.62074\ s

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.62074}{3}\\\Rightarrow t'=0.206913\ s

For second drop time is given by

t''=2t'\\\Rightarrow t''=2\times 0.2069133\\\Rightarrow t''=0.4138266\ s

Distance from second drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.4138266^2\\\Rightarrow s=0.839993\ m

Distance from second drop is 0.83999 m

Distance from third drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.206913^2\\\Rightarrow s=0.20999\ m

Distance from third drop is 0.20999 m

6 0
4 years ago
A graph titled Distance as a Function of Time with horizontal axis time (seconds) and vertical axis distance (meters). A straigh
yanalaym [24]

Answer:

3 m

Explanation:

6 0
3 years ago
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