Answer:
F = 20.4 i ^
Explanation:
This exercise can be solved using the ratio of momentum and amount of movement.
I = F t = Dp
Since force and amount of movement are vector quantities, each axis must be worked separately.
X axis
Let's look for speed
cos 45 = vₓ / v
vₓ = v cos 45
vₓ = 8 cos 45
vₓ = 5,657 m / s
We write the moment
Before the crash p₀ = m vₓ
After the shock
= -m vₓ
The variation of the moment Δp = mvₓ - (-mvₓ) = 2 m vₓ
The impulse on the x axis Fₓ t = Δp
Fₓ = 2 m vₓ / t
Fx = 2 0.450 5.657 / 0.250
Fx = 20.4 N
We perform the same calculation on the y axis
sin 45 = vy / v
vy = v sin 45
vy = 8 sin 45
vy = 5,657 m / s
We calculate the initial momentum po = m 
Final moment
= m
Variations moment Δp = m
- m
= 0
Force in the Y-axis
= 0
Therefore the total force is
F = fx i ^ + Fyj ^
F = Fx i ^
F = 20.4 i ^
Because that's called friction. When to things collide it causes friction which makes them stop rolling>
Answer:
a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s
Explanation:
a)
- As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
- This means that we can use the kinematic equations for displacements along both axes.
- In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

- In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:

- For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

b)
- From (2) we can get the position on the y-axis (displacement from the origin) as follows:

c)
- In the x- direction, we can find the component of the velocity along this direction, as follows:

- Replacing by the values, we have:

d)
- As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:
vfy = voy = -4 m/s
Answer:
0.83999 m
0.20999 m
Explanation:
g = Acceleration due to gravity = 9.81 m/s² = a
s = 189 cm

When the time intervals are equal, if four drops are falling then we have 3 time intervals.
So, the time interval is

For second drop time is given by

Distance from second drop

Distance from second drop is 0.83999 m
Distance from third drop

Distance from third drop is 0.20999 m