Answer:
Option B
Step-by-step explanation:
Refer to the Attachment for steps.
I might be wrong but don’t you need two equations to do the elimination process?
the probability of selecting a blue crayon for the bag is 16.7% while estimate probability of selecting a red crayon is 20% and the most likely crayon to be selected is brown crayon and also the possibility of getting a real possibility of the number of crayons in the bag is 60
1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5
