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Alenkinab [10]
3 years ago
9

PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER

Mathematics
1 answer:
choli [55]3 years ago
3 0
The correct answer is B :)
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Answer

The number of followers is decreasing

Step-by-step explanation:

The function is decreasing over time since the base of the exponent is less than 1. The value is greater when t is 0 and decreases as t increases.

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In order for the two figures shown below to be similar, the length of the
svp [43]

Answer: 66

Step-by-step explanation:

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3 years ago
Number 15 really need help
Leokris [45]
$9 a day for 8 days.

So, for every day that went by they earned $9. In other words the answer is the Amount of Money Earned per day multiplied by the number of days!

So!

$9 * 8days

Or you can also think of it as this: 
9+9+9+9+9+9+9+9

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8 0
3 years ago
Read 2 more answers
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
How do i solve this problem? how did they get 2.5?
WARRIOR [948]
Take the GCF (-8t) of the given expression.

You'll get -8t(2t-5).

Now, set each equal to zero and solve for x.

-8t = 0 2t-5=0

t=0 t = 5/2 (Or 2.5 seconds)
6 0
3 years ago
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