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3 years ago

Juliet wants to know if the chicken broth in this beaker will fit into this rectangular food storage container.

Mathematics

1 answer:

Blizzard [7]3 years ago

4 0

Answer:

Doesn't fit

Step-by-step explanation:

There are 2.4litres in the beaker if you count the lines; they increment by 0.4 litres each. The volume of the storage container is 20 x 15 x 7 = 2100 cm^3 (cm cubed). 1 cm^3 = 1 ml; the cube can hold 2100 mL which is 2.1 litres, which is less than the 2.4 litres in the beaker, therefore it will not fit.

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Ipatiy [6.2K]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

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3 years ago

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yuradex [85]

Answer:

-10 - 1 = x

Step-by-step explanation:

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3 years ago