Chemical change
Hope this helps!
Answer:
Molality = 0.43 m
Explanation:
Given data:
Mass of barium sulfide = 25.4 g
Mass of water = 349 g (349 g/1000 = 0.349 Kg)
Molality of water = ?
Solution:
Number of moles of barium sulfide:
Number of moles = mass/molar mass
Number of moles = 25.4 g/169.39 g/mol
Number of moles = 0.15 mol
Molality:
Molality = number of moles o f solute/ Kg of solvent
Molality = 0.15 mol / 0.349 Kg
Molality = 0.43 m
Answer:
The empty space between the atomic cloud of an atom and its nucleus is just that: empty space, or vacuum. ... Electrons are thus 'spread out' quite a bit in their orbits about the nucleus. In fact, the wave-functions for electrons in s-orbitals about a nucleus actually extend all the way down into the nucleus itself.
Compound A : SnCl2
the mass ratio of Cl and Sn: 71 g Cl/ 119 g Sn = 0.579 g Cl/ 1 g Sn
Compound B: the ratio of mass of chlorine per 1 g Sn is twice the ratio of chlorine per 1 g Sn in compound A => 1,194 g Cl/ 1 g Sn = 142,086 g Cl/ 119 g Sn
=> the number of chlorine/ 1 atom Sn = 142.086/ 35.5 = 4.
=> the formula of B: SnCl4