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adell [148]
2 years ago
14

SO3 (g) + H2O (l) ------> H2SO4 (l)

Chemistry
1 answer:
earnstyle [38]2 years ago
7 0

Answer:

Moles of H_2O reacted = 0.1529 moles

Explanation:

Mass of H_2SO_4 obtained = 15 g

Thus, formation of the product can be used to determine the moles of water reacted as:-

Molar mass of H_2SO_4 = 98.079 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{15\ g}{98.079\ g/mol}

Moles_{H_2SO_4}= 0.1529\ mol

According to the given reaction:-

SO_3+H_2O\rightarrow H_2SO_4

1 mole of H_2SO_4 forms when 1 mole of H_2O is reacted

So,

0.1529 mole of H_2SO_4 forms when 0.1529 mole of H_2O is reacted

Thus, Moles of H_2O reacted = 0.1529 moles

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timurjin [86]
In a closed system, heat should be conserved which means that the heat produced in the calorimeter is equal to the heat released by the combustion reaction. We calculate as follows:

Heat of the combustion reaction = mC(T2-T1)
                                                          = 1 (1.50) (41-21)
                                                          = 30 kJ
7 0
3 years ago
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There are five constitutional isomers with the molecular formula C6H14. When treated with chlorine at 300°C, isomer A gives a mi
ozzi

Answer:

Pentane or 2,2-dimethylbutane  

Explanation:

I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.

The results are

Isomer 1— three sets of equivalent hydrogens

Isomer 2— five sets of equivalent hydrogens

Isomer 3— four sets of equivalent hydrogens

Isomer 4— two sets of equivalent hydrogens

Isomer 5— three sets of equivalent hydrogens

Each set will give one monochloro substitution product.

4 = A. Two monochloro isomers.

2 = B. Five monochloro isomers.

3 = C. Four monochloro isomers.

Isomers 1 and 5 each give three monochloro isomers.

Thus, we cannot assign Structure D definitively.

D is either pentane or 2,2-dimethylbutane.

5 0
3 years ago
70 points and will give brainliest
ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

  • We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
  • From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
  • We find the number of moles of the baking powder that went into the reaction using the expression below:

                Number of moles = \frac{mass}{molar mass}

                Number of moles =  \frac{15}{84} = 0.179mole

  • From the equation of the reaction, we can find the number of moles of the citric acid:

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with \frac{0.179}{3}:

          This yields 0.059mole of citric acid

  • To find the volume of the citric acid, we use the mole expression below:

    Volume of citric acid = \frac{number of moles}{concentration}

Volume of citric acid = \frac{0.059}{0.8} = 0.074L

Expressing in mL gives 74mL

               

4 0
3 years ago
how many milliliters of 1.50 m hno3 contain enough nitric acid to dissolve an old copper penny with a mass of 3.94 g?
Lerok [7]
Molar mass HNO₃ = 63.0 g/mol

number of moles = 3.94 / 63.0 => 0.0625 moles

Volume = moles / molarity

V = 0.0625 / 1.50

V = 0.04166 L x 1000 = 41.66 mL

hope this helps!

5 0
3 years ago
When HClO2 is dissolved in water, it partially dissociates according to the equation
Natasha_Volkova [10]

Answer:

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

Explanation:

Recall that , depression present in freezing point is calculated with the formulae = solute particles Molarity x KF

0.3473 = m * 1.86

Solving, m = 0.187 m

Moles of HClO2 = mass / molar mass = 5.85 / 68.5 = 0.0854 mol

Molality = moles / mass of water in kg = 0.0854 / 1 = 0.0854 m

Initial molality

Assuming that a % x of the solute dissociates, we have the ICE table:

                 HClO2         H+    +   ClO2-

initial concentration:       0.0854                    0             0

final concentration:      0.0854(1-x/100)   0.0854x/100   0.0854x / 100

We see that sum of molality of equilibrium mixture = freezing point molality

0.0854( 1 - x/100 + x/100 + x/100) = 0.187

2.1897 = 1 + x / 100

x = 100 * 1.1897 = 118.97 %, which is > 100 meaning that all of the HClO2 dissociates

3 0
3 years ago
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